谁能告诉我析构函数出了什么问题?如果我删除它,一切正常。
#include "stdafx.h"
#include <stdio.h>
#include <string.h>
#include <conio.h>
class DynString
{
private :
char *string;
int size;
public :
DynString(const char *tab)
{
string = new char[strlen(tab)];
size = strlen(tab);
if (string != NULL)
{
strcpy(this->string, tab);
}
}
DynString(const DynString& s)
{
string = new char[s.size];
if (string != NULL)
{
strcpy(string, s.string);
size = s.size;
}
else size = 0;
}
int Size() const
{
return size;
}
const char* CStr()
{
return string;
}
DynString& operator +=(const char* tab)
{
char *bufor = new char[size + strlen(tab)];
if (bufor != NULL)
{
strcpy(bufor, string);
strncat(bufor, tab, strlen(tab));
string = new char[strlen(bufor) + sizeof(char)];
}
if (string != NULL)
{
strcpy(string, bufor);
size = strlen(string);
}
return *this;
}
DynString& operator !()
{
unsigned int size = strlen(string);
for (unsigned int i = 0; i < size; i++)
{
if (string[i] >= 97 && string[i] <= 122)
{
string[i] -= 32;
}
else if (string[i] >= 65 && string[i] <= 90)
{
string[i] += 32;
}
}
return *this;
}
~DynString();
};
DynString::~DynString()
{
if (size == 0)
{
delete string;
}
else
{
delete[] string;
}
}
int _tmain(int argc, _TCHAR* argv[])
{
DynString string("Test words.");
printf("String %s\n", string.CStr());
printf("Characters: %i\n", string.Size());
DynString copy = string;
printf("Copy %s\n", copy.CStr());
printf("Characters: %i\n", copy.Size());
copy += " - first fragment -";
copy += " second fragment.";
printf("Copy %s\n", string.CStr());
printf("Characters: %i\n", string.Size());
printf("Copy %s\n", copy.CStr());
printf("Characters: %i\n", copy.Size());
!string;
printf("String %s\n", string.CStr());
printf("\nEnd.");
_getch();
return 0;
}
您的析构函数应为:
if(string!=NULL)
{
delete[] string;
}
要不就
delete[] string;
(考虑到delete[]
荷兰国际集团一个NULL
指针是安全的)。
请记住:与一起分配的所有内容都new[]
必须由破坏delete[]
;分配给的所有内容都new
必须用销毁delete
。
编辑:
此外,你应该分配string
与strlen(tab)+1
空间,以适应终止空字节(对于拷贝构造函数,这种手段s.size+1
)。
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