我正在尝试使用PDO更新数据库,但无法正常工作。我可以毫无困难地选择数据,但是更新将无法进行。我没有收到错误消息,但是执行查询后,数据库中没有任何变化。
这是我的代码,此方法是类的一部分,因此定义了pdo,但我不会将整个代码粘贴到此处,只是将重要部分粘贴到了这里:
public function modify($q, $data){
try{
$stmt = $this->pdo->prepare($q);
$stmt->execute($data);
return true;
}
catch(PDOException $e){
$this->error = $e->getMessage();
return false;
}
}
和:
$question = new Question(base64_decode($_POST['value']), $_POST['question'], $_POST['code'], $_POST['number'], $_POST['answer1'],
$_POST['answer2'], $_POST['answer3'], $_POST['answer4'], $_POST['correct_answer']);
$array = [
':qid' => $question->qid,
':question' => $question->question,
':code' => $question->code,
':number' => $question->number ,
':answer1' => $question->answer1,
':answer2' => $question->answer2,
':answer3' => $question->answer3,
':answer4' => $question->answer4,
':correct_answer' => $question->correct_answer#9
];
$q = 'UPDATE questions SET question = :question AND code = :code AND number = :number AND
answer_1 = :answer1 AND answer_2 = :answer2 AND answer_3 = :answer3 AND answer_4 = :answer4
AND correct_answer = :correct_answer WHERE question_id = :qid';
$db->query('SET NAMES UTF8');
$db->modify($q, $array);
谢谢!
更新语句用逗号“ and”分隔要更新的字段:
$q = 'UPDATE questions SET question = :question, code = :code,
number = :number, answer_1 = :answer1, answer_2 = :answer2,
answer_3 = :answer3, answer_4 = :answer4,
correct_answer = :correct_answer
WHERE question_id = :qid';
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