如何确定文本文件中有多少个奇数和偶数？

Jamef 发表于 Dev

贾梅夫

def main():

    #Open the numbers.txt file
    File=open ('numbers.txt', 'r')

    #This reads the lines in the file
    for line in File:
        #Convert line to float
        amount=float(line)

        #format and display the amount
        print(format(amount,'.2f'))
        print("\n")

    #close the file
    File.close()

    for amount in range (0,13):
        if (amount%2==0):
            print amount


main()

这是输出的样子：

53
15
21
49
8
98
55
21
76
75
53
28

Total of even numbers:[]
Total of odd numbers:[]

帕德拉克·坎宁安（Padraic Cunningham）

除非您实际上在number.txt中有浮点数，否则只需将其强制转换为int即可：

with open("numbers.txt") as f:
    odds = []
    evens = []
    for num in f:
        num = int(num)
        if num % 2: # if there is a remainder num is odd
            odds.append(num) 
        else: # else it must be even
            evens.append(num)

print("All even numbers: {}".format(evens))
print("All odd numbers: {}".format(odds))
print("Total amount of even numbers: {}".format(len(evens))) # len will be total even nums
print("Total amount of odd numbers: {}".format(len(odds)))

如果您只想要计数：

with open("numbers.txt") as f:
    odd,even = 0, 0
    for num in f:
        num = int(num)
        if num % 2:
            odd += 1
        else:
            even += 1

print("Total amount of even numbers: {}".format(even))
print("Total amount of odd numbers: {}".format(odd))

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