我有4个标签，所有标签都有UIWebView。我希望第一个选项卡应该加载并立即显示，而不必等待其他人加载。为此，我在UITabBarController课堂上这样做了：
for(UIViewController * viewController in self.viewControllers){
if(![[NSUserDefaults standardUserDefaults]boolForKey:@"isSessionExpired"])
{
if((int)[self.viewControllers indexOfObject:viewController] != 4)
{
viewController.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:viewController];
[viewController view];
}
}
}
但是主线程等待所有选项卡加载。
我试图与GCD使用dispatch_async
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_HIGH, 0), ^{ // 1
dispatch_async(dispatch_get_main_queue(), ^{
UIViewController *firstContrl = [self.viewControllers objectAtIndex:0];
firstContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:firstContrl];
[firstContrl view];
dispatch_async(dispatch_get_main_queue(), ^{ // 2
UIViewController *secContrl = [self.viewControllers objectAtIndex:1];
secContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:secContrl];
[secContrl view];
dispatch_async(dispatch_get_main_queue(), ^{ // 3
UIViewController *thirdContrl = [self.viewControllers objectAtIndex:2];
thirdContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:thirdContrl];
[thirdContrl view];
dispatch_async(dispatch_get_main_queue(), ^{ // 4
UIViewController *fourthContrl = [self.viewControllers objectAtIndex:3];
fourthContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:fourthContrl];
[fourthContrl view];
});
});
});
});
});
但这也不起作用。显示第一个选项卡需要花费相同的时间。
如何解决？
埃姆.. GCD和一个UIWebView的 -loadRequest:，你认为是行不通的。上面的所有代码都等于：
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_HIGH, 0), ^{
dispatch_async(dispatch_get_main_queue(), ^{
UIViewController *firstContrl = [self.viewControllers objectAtIndex:0];
firstContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:firstContrl];
[firstContrl view];
UIViewController *secContrl = [self.viewControllers objectAtIndex:1];
secContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:secContrl];
[secContrl view];
UIViewController *thirdContrl = [self.viewControllers objectAtIndex:2];
thirdContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:thirdContrl];
[thirdContrl view];
UIViewController *fourthContrl = [self.viewControllers objectAtIndex:3];
fourthContrl.tabBarItem.tag = (int)[[self viewControllers] indexOfObject:fourthContrl];
[fourthContrl view];
});
});
要解决您的问题，您需要实施，具体取决于- (void)webViewDidFinishLoad:(UIWebView *)webView。这个想法是：
如果我是你，我将以以下方式实现它：
// FirstViewController.h
extern NSString * const FirstViewControllerDidLoadWebView;
// FirstViewController.m
NSString * const FirstViewControllerDidLoadWebView=@"FirstViewControllerDidLoadWebView";
- (void)webViewDidFinishLoad:(UIWebView *)webView
{
// notify other controllers, to let them load their web views:
[[NSNotificationCenter defaultCenter] postNotificationName:FirstViewControllerDidLoadWebView
object:nil];
}
- (void)webView:(UIWebView *)webView didFailLoadWithError:(NSError *)error
{
// loading failed. Try to load it few more times but anyway notify other controllers after:
[[NSNotificationCenter defaultCenter] postNotificationName:FirstViewControllerDidLoadWebView
object:nil];
}
之后，“订阅”所有其他（仅选项卡）视图控制器以进行FirstViewControllerDidLoadWebView通知，并在WebView到达后加载其WebView。
有关更多详细信息，请检查NSNotificationCenter和UIWebViewDelegate
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