我正在尝试编写脚本以将代码的结果与我已经建立的结果进行比较以进行回归测试

我一直在尝试编写一个bash脚本来运行我的代码，然后将最终输出与以前的运行（在正确的结果下）进行比较，并在return.dat下比较。目的是告诉我代码是否在与之前相同的迭代次数中收敛，并且结果是否位于.dat文件中基准测试结果的0.1％之内。到目前为止，我已经收到了很多语法错误，即使我摆脱了它们，变量reg1，reg2，reg3等也只能将0存储为一个值。

#!/bin/bash
rm *.dat
rm *.vtu
FiniteVolume.serial export FORT_FMT_RECL=250
mv finaloutput.dat regression
cd regression
readarray filecontent < regression_test.dat
echo $filecontent
readarray filecontent2 < finaloutput.dat
echo $filecontent2
((reg1=${filecontent[1]}))
((reg2=${filecontent[2]}))
((reg3=${filecontent[3]}))
((reg4=${filecontent[4]}))
echo reg1
echo $reg1

((exm1=${filecontent2[1]}))
((exm2=${filecontent2[2]}))
((exm3=${filecontent2[3]}))
((exm4=${filecontent2[4]}))

if ((reg1 = exm1)); then
     echo "iteration count is equal" 
elif ((sqrt((reg2- exm2)^2)/reg2 < 1e-1)) ; then
     echo "Lift coefficient error is less than .1 percent"
elif ((sqrt((reg2- exm2)^2)/reg2 > 1e-1)); then
     echo "Lift Coefficient test failed"
elif ((sqrt((reg3- exm3)^2)/reg3 < 1e-1)); then
     echo "Drag coefficient error is less then .1 percent"
elif ((sqrt((reg3- exm3)^2)/reg3 > 1e-1)); then
      echo "Drag Coefficient test failed"
elif ((sqrt((reg4- exm4)^2)/reg4 < 1e-1)); then
     echo "Residual error is less than .1 percent"
elif ((sqrt((reg2- exm2)^2)/reg2 > 1e-1)); then
     echo "Residual test failed"
fi

cd ..
rm *.dat
rm *.vtu

结果如下：

14159 0.39700296920172 9.560746238889790E-002 9.992898637502570E-013
14159 0.39700296920172040 9.56074623888978209E-002 9.99311202935717304E-013
./regression_test.sh: line 11: reg1=: syntax error: operand expected (error token is "=")
./regression_test.sh: line 12: reg2=: syntax error: operand expected  (error token is "=")
./regression_test.sh: line 13: reg3=: syntax error: operand expected (error token is "=")
./regression_test.sh: line 14: reg4=: syntax error: operand expected  (error token is "=")
reg1

./regression_test.sh: line 25: ((: sqrt((reg2- exm2)^2)/reg2 < 1e-1: syntax error in expression (error token is "((reg2- exm2)^2)/reg2 < 1e-1")
./regression_test.sh: line 27: ((: sqrt((reg2- exm2)^2)/reg2 > 1e-1: syntax error in expression (error token is "((reg2- exm2)^2)/reg2 > 1e-1")
./regression_test.sh: line 29: ((: sqrt((reg3- exm3)^2)/reg3 < 1e-1: syntax error in expression (error token is "((reg3- exm3)^2)/reg3 < 1e-1")
./regression_test.sh: line 31: ((: sqrt((reg3- exm3)^2)/reg3 > 1e-1: syntax error in expression (error token is "((reg3- exm3)^2)/reg3 > 1e-1")
./regression_test.sh: line 33: ((: sqrt((reg4- exm4)^2)/reg4 < 1e-1: syntax error in expression (error token is "((reg4- exm4)^2)/reg4 < 1e-1")
./regression_test.sh: line 35: ((: sqrt((reg2- exm2)^2)/reg2 > 1e-1: syntax error in expression (error token is "((reg2- exm2)^2)/reg2 > 1e-1")

如何更改脚本以消除语法错误，并允许变量将要存储读取数据的数组作为元素的值？过去的一天中，我一直在阅读有关bash算术和脚本的内容，但未能获得对执行此操作的最佳方法的清晰解释，因此我们将不胜感激。