调试器不会从调用函数返回到被调用函数

我已经获得了我的代码，并且正在对下面的代码进行debug（myfun1）。如图所示，我在第13行设置了一个断点。

我的代码如下

myfun1 = function()
{
  print("This is myfun1, before calling the myfun2()")
  myfun2()
  print("This is myfun1, after calling the myfun2()")
  print("Does the debugger come back to this point")
}

myfun2 = function()
{
  print("This is myfun2, before calling the myfun3()")
  myfun3()
  print("This is  myfun2, after calling the myfun3()")
  print("This is the last but one line of myfun2()")
  print("This is the last line of myfun2()")
}

myfun3 = function()
{
  print("This is myfun3")
}

这些是我用于调试的步骤顺序

1. 我从myfun1开始，然后在第4行上执行“ s”以进入myfun2（）
2. 调试器直接将我带到第13行，因为我设置了断点
3. 现在，我在myfun2（）中执行了n次，这使我进入了后续的行，即line14和line15 resp。
4. But, if I do 'n' on line 15, I expect it to go back to myfun1(). However, it just exits(I was able to get it to go back to myfun1() by setting a breakpoint in myfun1 after myfun2() is called(say in line5 or line6), but shouldn't it return even otherwise?)

See my debug log below

> debugSource('~/Desktop/foo1.R')
> debug(myfun1)
> myfun1()
debugging in: myfun1()
debug at ~/Desktop/foo1.R#2: {
    print("This is myfun1, before calling the myfun2()")
    myfun2()
    print("This is myfun1, after calling the myfun2()")
    print("Does the debugger come back to this point")
}
Browse[2]> c
[1] "This is myfun1, before calling the myfun2()"
[1] "This is myfun2, before calling the myfun3()"
[1] "This is myfun3"
Called from: eval(expr, envir, enclos)
Browse[1]> n
debug at ~/Desktop/foo1.R#13: print("This is  myfun2, after calling the myfun3()")
Browse[2]> n
[1] "This is  myfun2, after calling the myfun3()"
debug at ~/Desktop/foo1.R#14: print("This is the last but one line of myfun2()")
Browse[2]> n
[1] "This is the last but one line of myfun2()"
debug at ~/Desktop/foo1.R#15: print("This is the last line of myfun2()")
Browse[2]> n
[1] "This is the last line of myfun2()"
[1] "This is myfun1, after calling the myfun2()"
[1] "Does the debugger come back to this point"
exiting from: myfun1()