仅当值不为空时更新mySQL

三明治

我正在处理一个更新查询,其中值仅在值不为null或为空时才应更新。现在,无论值如何,它都会更新所有内容。请帮我解决这个问题。

$query = "UPDATE bundels 
SET batchkosten = CASE WHEN  ". $_POST['batchkosten'] . " IS NOT NULL
                   THEN  ". $_POST['batchkosten'] . "
                   ELSE batchkosten
              END CASE,
              CASE WHEN   ". $_POST['maandelijkse_kosten'] . "  IS NOT NULL
                   THEN   ". $_POST['maandelijkse_kosten'] . " 
                   ELSE maandelijkse_kosten
              END CASE,
              CASE WHEN   ". $_POST['aanmeldkosten'] . "  IS NOT NULL
                   THEN   ". $_POST['aanmeldkosten'] . " 
                   ELSE aanmeldkosten
              END CASE,
              CASE WHEN   ". $_POST['transactiekosten'] . "  IS NOT NULL
                   THEN   ". $_POST['transactiekosten'] . " 
                   ELSE transactiekosten
              END CASE,
              CASE WHEN   ". $_POST['referral'] . "  IS NOT NULL
                   THEN   ". $_POST['referral'] . " 
                   ELSE referral
              END CASE,
              CASE WHEN   ". $_POST['actief'] . "  IS NOT NULL
                   THEN   ". $_POST['actief'] . " 
                   ELSE actief
              END CASE
              WHERE bundel_id = ". $_POST['bundel_id'] . "";
        $result = mysql_query($query, $db) or die ('FOUT: werkt niet'); 
            header ("Location: vergelijker_bewerken.php");
        } else {
            $bundels = mysql_query("SELECT bundels.psp_id, psp.psp_id, psp_naam, bundels.bundel_id, batchkosten, maandelijkse_kosten, aanmeldkosten, transactiekosten, referral, actief from bundels
                                    JOIN psp
                                ON psp.psp_id = bundels.psp_ID"); 
}
于尔根
  1. 使用Prepared Statements可以转义用户输入,并避免SQL语法错误和SQL注入。
  2. 您可以使用 case

    UPDATE bundels 
    SET batchkosten = case when ? is not null and length(?) > 0
                           then ?
                           else batchkosten
                      end,
    ...
    

您当前的查询转换为(实际上应该引发错误)

UPDATE bundels 
SET batchkosten = CASE WHEN ? length(?) > 0 
                       THEN ?
                       ELSE batchkosten 
                  END 
WHERE bundel_id = ? 

但是改用:

SET batchkosten = CASE WHEN ? is not null and length(?) > 0 

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