我在第一个片段调用中有两个片段，AsyncTask并获取了一些json值。然后我想将JSON值传递给第二个片段的TextViews。在片段之间传递json值的最佳方法是什么？
这是我AsyncTask的Fragment 1
class LoadingAccountEntry extends AsyncTask<String, String, String> {
@Override
protected void onPreExecute() {
}
@Override
protected String doInBackground(String... args) {
String response;
Map<String, Object> data = new LinkedHashMap<String, Object>();
data.put(SESSION, sessionId);
data.put(MODULE_NAME, module_name);
data.put(ID, entry_id != null ? entry_id : "");
data.put(
SELECT_FIELDS,
(selectFields != null && selectFields.length != 0) ? new JSONArray(
Arrays.asList(selectFields)) : "");
try {
JSONArray nameValueArray = new JSONArray();
if (linkNameToFieldsArray != null
&& linkNameToFieldsArray.size() != 0) {
for (Entry<String, List<String>> entry : linkNameToFieldsArray
.entrySet()) {
JSONObject nameValue = new JSONObject();
nameValue.put("name", entry.getKey());
nameValue.put("value", new JSONArray(entry.getValue()));
nameValueArray.put(nameValue);
}
}
data.put(LINK_NAME_TO_FIELDS_ARRAY, nameValueArray);
String restData = org.json.simple.JSONValue.toJSONString(data);
HttpClient httpClient = new DefaultHttpClient();
HttpPost req = new HttpPost(restURL);
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair(METHOD, GET_ENTRY));
nameValuePairs.add(new BasicNameValuePair(INPUT_TYPE, JSON));
nameValuePairs.add(new BasicNameValuePair(RESPONSE_TYPE, JSON));
nameValuePairs.add(new BasicNameValuePair(REST_DATA, restData));
req.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Send POST request
httpClient.getParams().setBooleanParameter(
CoreProtocolPNames.USE_EXPECT_CONTINUE, false);
HttpResponse res = httpClient.execute(req);
response = EntityUtils.toString(res.getEntity());
// Log.d("Responce", response.toString());
if (response == null) {
Log.e("Error !", "faild to connect !");
}
JSONObject responseObj = new JSONObject(response);
JSONArray jArray = responseObj.getJSONArray(ENTRY_LIST);
for (int i = 0; i < jArray.length(); i++) {
JSONObject obj = jArray.getJSONObject(i);
// Log.d("obj", obj.toString());
// JSONObject objName = new JSONObject("name");
id = obj.getString("id");
Log.d("id", id);
JSONObject name_value_list = obj
.getJSONObject("name_value_list");
JSONObject assignedUserName = name_value_list
.getJSONObject("assigned_user_name");
assigned_user_name = assignedUserName.getString("value");
Log.d("assigned_user_name", assigned_user_name);
JSONObject modifiedByName = name_value_list
.getJSONObject("modified_by_name");
modified_by_name = modifiedByName.getString("value");
Log.d("modified_by_name", modified_by_name);
}
} catch (JSONException e) {
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
}
这 Fragment 2
public class Fragment_account_details extends Fragment {
TextView name, officePhone,fax;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_account_details, container,false);
name = (TextView) rootView.findViewById(R.id.text_name);
fax = (TextView) rootView.findViewById(R.id.text_fax);
return rootView;
}
您可以使用bundle将数据传递给Fragment_account_details，如下所示：
Fragment fragment = new Fragment_account_details();
Bundle bundle = new Bundle();
bundle.putString("name", name);
fragment.setArguments(bundle);
现在在您的Fragment_account_details onCreateView中，您可以执行以下操作：
String name= getArguments().getString("name");
像这样你可以传递值。希望这会有所帮助。
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我来说两句