提交JSP表单时与Hibernate的一对一关系以及共享密钥错误

ian

我正在尝试创建2个表,其中第一个表具有主键,而另一个表具有它的键。我正在使用Spring mvc + hibernate,并且在提交jsp表单时显示了此错误:

尝试从空的一对一属性[model.TableB.resource]分配ID;嵌套的异常是org.hibernate.id.IdentifierGenerationException:尝试从空的一对一属性[model.TableB.resource]分配ID

表A:

@Entity
public class TableA{

    @Id
    private String sNum

    @OneToOne(mappedBy = "resource",cascade = CascadeType.ALL)
    private TableB tableB;

    //other fields, getter setters
}

表B:

@Entity
public class TableB{

    @Id
    private String id

    @MapsId
    @OneToOne
    @JoinColumn(name="resourceId")
    private TableA resource;

    //other fields, getter setters
}

这些实体将以下内容输出到mysql中:

TableA
+------+---------------+---------------+-----------------+
| sNum | column1tableA | column2tableA | ..other columns |
+------+---------------+---------------+-----------------+
| PK   |               |               |                 |
+------+---------------+---------------+-----------------+


TableB
+-------------------+---------+-----------------+
|    resourceId     | column1 | ..other columns |
+-------------------+---------+-----------------+
| PK FK from TableA |         |                 |
+-------------------+---------+-----------------+

服务:

public class tableAService {
    @Autowired
    TableARepository tableARepository; //this repository extends from jpa repository

    public void create(TableA tableA){
    tableARepository.save(tableA); 
    }
}

控制器:

@RequestMapping(value = "/createTableA", method = RequestMethod.GET)
public String getCreateTableAPage(Model model){
    if(!model.containsAttribute("tableA"))
        model.addAttribute("tableA", new TableA());

    return "createTableA";
} // this returns the registration page

@RequestMapping(value="/doCreateRe", method = RequestMethod.POST)
public String doCreateRe(@Valid @ModelAttribute("tableA") TableA tableA, BindingResult result){
    if(result.hasErrors()){

        return "redirect:/createPage";
    }try{
        myservice.create(tableA);
        return "viewPage";
    }catch(Exception e){
        System.out.println(e.getMessage());
        return "error";
    }
} // this handles the onsubmit of the registration page

EDIT-2(请参阅下面的示例输出):提交表单时,应将表A的字符串ID(由用户手动在表单上输入)保存为表​​B上的外键。例如,我想保存一个tableA类型的对象,我将在jsp表单上手动为其分配ID,填充同一页面/表单上的其他tableA字段以及相关的tableB对象(即tableA.tableB。 someField)也存在于表单上(提交“ registration”表单后,它将在表A和表B上创建新行,表B的键将是表A的键-见下文)

createTableA页面的JSP:

<form:form  modelAttribute="tableA" method="POST" action="doCreateRe">
  ...
 <form:input path="sNum" required="true"/> <!-- sample input is abc123 -->
 <form:input path="column1tableA" required="true"/> <!-- sample input is chocolate -->
 <form:input path="column2tableA" required="true"/> <!-- sample input is beer -->
 <form:input path="tableB.column1" required="true"/> <!-- sample input is isDelicious -->
 <form:input path="tableB.column2" required="true"/> <!-- sample input is isBetter -->
 ...
</form:form>

提交表单后应显示在数据库中的输出:

表A:

+------------+---------------+---------------+
|    sNum    | column1tableA | column2tableA |
+------------+---------------+---------------+
| abc123 PK  | chocolate     | beer          |
+------------+---------------+---------------+

表B:

+------------+-------------+----------+
| resourceId |   column1   | column2  |
+------------+-------------+----------+
| abc123 FK  | isDelicious | isBetter |
+------------+-------------+----------+ 
ian

好吧,我终于找到了解决办法。参考

在TableA实体上,我需要为其设置器添加额外的一行。

@Entity
public class TableA{

    @Id
    private String sNum

    @OneToOne(mappedBy = "resource",cascade = CascadeType.ALL)
    private TableB tableB;

    public TableB getTableB() {         
        return tableB;
    }

    public void setTableB(TableB tableB) {
        this.tableB = tableB;
        tableB.setResource(this); // added this line of code
    }

    //other fields, getter setters
 }

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