在使用Gideros Studio的游戏中,我有一个具有多个参数的函数。我想在一个参数上调用我的函数,然后在另一个参数上调用。这可能吗?
这是我的功能:
local function wiggleroom(a,b,c)
for i = 1,50 do
if a > b then
a = a - 1
elseif a < b then
a = a + 1
elseif a == b then
c = "correct"
end
return c
end
end
我想a
用相提并论b
,但调用函数的b
和c
以后。例如:
variable = (wiggleroom(variable, b, c) --if variable was defined earlier
variable2 = (wiggleroom(a, variable2, c)
variable3 = (wiggleroom(a, b, variable3)
我还希望能够对多个对象使用此功能(两次调用每个参数)。
如果我对您的理解正确,则可以考虑使用lua版本的类。如果您不认识他们,则可能要看看这个。
例子:
tab = {}
function tab:func(a, b, c) -- c doesn't get used?
if a then self.a = a end
if a then self.b = b end
if a then self.c = c end
for i = 1,50 do
if self.a > self.b then
self.a = self.a - 1
elseif self.a < self.b then
self.a = self.a + 1
elseif self.a == self.b then
self.c = "correct"
end
end
return c -- not really necessary anymore but i leave it in
end
function tab:new (a,b,c) --returns a table
o = {}
o.a = a
o.b = b
o.c = c
setmetatable(o, self)
self.__index = self
return o
end
--how to use:
whatever1 = tab:new(1, 60) --set a and b
whatever2 = tab:new() --you also can set c here if needed later in the function
whatever1:func() --calling your function
whatever2:func(0,64)
print(whatever1.a) -->51
print(whatever2.a) -->50
print(whatever1.c) -->nil
whatever1:func() --calling your function again
whatever2:func()
print(whatever1.a) -->60
print(whatever2.a) -->64
print(whatever1.c) -->correct
print(whatever2.c) -->correct
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