试图做出决策树

Name    Hair    Eyes    Shirt   Glasses Smiling Hat
Alice   BROWN   BLUE    GREEN     YES   YES     NO
Bob     BROWN   BROWN   GREEN     YES   NO     YES
Dave    BROWN   BROWN   GREEN     NO    YES    YES
Emily   BROWN   HAZEL   RED       YES   YES    YES
Frank   BROWN   GREEN   GREEN     YES   YES     NO
Isabelle BROWN  HAZEL   GREEN     YES   YES     NO
Mallie  BROWN   BLUE    RED       YES   YES     NO
Nick    BROWN   BLUE    RED       NO    YES     NO
Philip  BROWN   GREEN   RED       NO    YES     NO
Quinn   BROWN   BROWN   RED       NO    YES     NO
Robert  BROWN   BROWN   RED       NO    YES     YES
Tucker  BROWN   BLUE    BLUE      NO    YES     NO
Wendy   BROWN   BLUE    RED       YES   NO     NO
Zander  BROWN   BROWN   BLUE      NO    YES    NO

我有这些角色，我正在尝试制作决策树，例如

 if (g.hairIsColor(Color.BROWN)) 
  {
   if(g.isWearingGlasses())
   {
     if(g.shirtIsColor(Color.GREEN))
     {
         k = "Bob";
       if(g.eyeIsColor(Color.GREEN))
       {
       k = "Frank";
       }
       if(g.eyeIsColor(Color.BLUE))
       {
       k = "Alice";
       break outerloop;
       }
       if(g.eyeIsColor(Color.HAZEL))
       {
       k = "Isabelle";
       }
     }
    if(g.eyeIsColor(Color.HAZEL))
    k = "Emily";
    if (g.isSmiling())
    k = "Mallie";
   }
    else if(g.eyeIsColor(Color.BROWN))
    {
     if (g.shirtIsColor(Color.RED))
     {
       if(g.isWearingHat())
       k = "Robert";
       else 
       k = "Quinn";
     }
     else if(g.shirtIsColor(Color.GREEN))
     k = "Dave";
     else
     k = "Zander";
    }
   else if(g.shirtIsColor(Color.RED))
   { 
    if(g.eyeIsColor(Color.BLUE))
    k = "Nick";
    if(g.eyeIsColor(Color.GREEN))
    k = "Philip";
   }
  else if(g.eyeIsColor(Color.BLUE) && g.shirtIsColor(Color.BLUE))
  k = "Tucker";
}

不幸的是，每个角色都花费了太多尝试，并且想知道是否有人可以帮助我？我试图将每个字符的尝试次数设置为10次或以下，但使用if语句似乎无法获得50％的帮助吗？我已经对其他头发的颜色进行了排序，但是棕色给我带来了麻烦