#include<stdio.h>
#include "a.h"
int main(){
s.a = 10;
printf("\n add : %d \n",add(2,2));
printf("\n sub : %d \n",sub(2,2));
printf("\n struct is : %d \n",s.a);
return 0;
}
#include<stdio.h>
int add(int a,int b){
return (a+b);
}
int sub(int a,int b){
return (a-b);
}
#ifndef A_HEADER
#define A_HEADER
typedef struct _s{
int a;
int b;
}s;
int add(int a,int b);
int sub(int a,int b);
#endif
O / p：
[root@s new]# ls
a.c a.h b.c include
[root@s new]# gcc -c a.c -o a.o
a.c: In function ‘main’:
a.c:4: error: expected identifier or ‘(’ before ‘.’ token
a.c:7: error: expected expression before ‘s’
我收到上述错误。找不到错误的原因
s是一种类型-您需要声明此类型的实例：
int main(){
s my_s; // my_s is an instance of the struct type `s`
my_s.a = 10; // initialise the `a` element of `my_s`
printf("\n add : %d \n",add(2,2));
printf("\n sub : %d \n",sub(2,2));
printf("\n struct is : %d \n",my_s.a); // <<<
return 0;
}
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