谷歌地图-变更中心

穆斯塔法·乔治

此代码会将地图中心移动到四个位置之一。它有效，但似乎很慢。是否可以通过预先缓存4张地图或类似的东西来获得更好的性能？也许每次都运行初始化函数会使我们减速吗？

<script src="https://maps.googleapis.com/maps/api/js?v=3.exp"></script>
<script src="../jquery/jquery.js" type="text/javascript"></script>  

    <script>


$( document ).ready(function() {

    var map;
    var montreal = new google.maps.LatLng(45.504 , -73.597);
    var newCenter = montreal
    var toronto = new google.maps.LatLng(43.65304 , -79.32129);
    var calgary = new google.maps.LatLng(50.99394, -114.16992);
    var vancouver = new google.maps.LatLng(49.18984, -123.17871);

    function initialize() {
      var mapDiv = document.getElementById('map-canvas');
      var mapOptions = {
        zoom: 10,
        center: newCenter
      }
      map = new google.maps.Map(mapDiv, mapOptions);
    }

    google.maps.event.addDomListener(window, 'load', initialize);

    $( "#location_1" ).on( "click", function() {
      newCenter = montreal;
      initialize();
    });

    $( "#location_2" ).on( "click", function() {
        newCenter = toronto;
        initialize();
    });
    $( "#location_3" ).on( "click", function() {
        newCenter = calgary;
        initialize();
    });
    $( "#location_4" ).on( "click", function() {
        newCenter = vancouver;
        initialize();
    });

});

  </script>
  </head>
  <body>
  <button id='location_1'>Montreal</button>
  <button id='location_2'>Toronto</button>
  <button id='location_3'>Calgary</button>
  <button id='location_4'>Vancouver</button>

    <div id="map-canvas"></div>

恭丸

您可以尝试使用setCenter()来更改地图的中心，而无需initialize再次调用该函数，这是

$( "#location_1" ).on( "click", function() {
  map.setCenter(montreal);
});

$( "#location_2" ).on( "click", function() {
    map.setCenter(toronto);
});
$( "#location_3" ).on( "click", function() {
    map.setCenter(calgary);
});
$( "#location_4" ).on( "click", function() {
    map.setCenter(vancouver);
});

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