我在R中的示例数据帧如下所示：
NAME ID SURVEY_YEAR REFERENCE_YEAR CUMULATIVE_SUM CUMULATIVE_SUM_REFYEAR
1 NAME1 47 1960 1959 -6 0
2 NAME1 47 1961 1960 -10 -6
3 NAME1 47 1963 1961 NA NA
4 NAME1 47 1965 1963 -23 -10
5 NAME2 259 2007 2004 -9 0
6 NAME2 259 2009 2007 NA NA
7 NAME2 259 2010 2009 NA NA
8 NAME2 259 2011 2010 NA NA
9 NAME2 259 2014 2011 -40 -9
我正在尝试做的是按照以下方式重新排列数据框。
NAME ID time YEAR CUMULATIVE_SUM id
NAME1 47 REFERENCE_YEAR 1959 0 1
NAME1 47 SURVEY_YEAR 1960 -6 1
NAME1 47 REFERENCE_YEAR 1960 -6 2
NAME1 47 SURVEY_YEAR 1961 -10 2
NAME1 47 REFERENCE_YEAR 1961 NA 3
NAME1 47 SURVEY_YEAR 1963 NA 3
NAME1 47 REFERENCE_YEAR 1963 -10 4
NAME1 47 SURVEY_YEAR 1965 -23 4
NAME2 259 REFERENCE_YEAR 2004 0 5
NAME2 259 SURVEY_YEAR 2007 -9 5
NAME2 259 REFERENCE_YEAR 2007 NA 6
NAME2 259 SURVEY_YEAR 2009 NA 6
NAME2 259 REFERENCE_YEAR 2009 NA 7
NAME2 259 SURVEY_YEAR 2010 NA 7
NAME2 259 REFERENCE_YEAR 2010 NA 8
NAME2 259 SURVEY_YEAR 2011 NA 8
NAME2 259 REFERENCE_YEAR 2011 -9 9
NAME2 259 SURVEY_YEAR 2014 -40 9
我正在尝试通过以下方式进行操作，但这并不是我想要的。
# read in data
data <- data.frame(NAME=c("NAME1", "NAME1","NAME1","NAME1","NAME2","NAME2","NAME2","NAME2","NAME2"),
ID=c(47,47,47,47,259,259,259,259,259),
SURVEY_YEAR=c(1960,1961,1963,1965,2007,2009,2010,2011,2014),
REFERENCE_YEAR=c(1959,1960,1961,1963,2004,2007,2009,2010,2011),
CUMULATIVE_SUM=c(-6,-10,NA,-23,-9,NA,NA,NA,-40),
CUMULATIVE_SUM_REFYEAR=c(0,-6,NA,-10,0,NA,NA,NA,-9))
# reshape data
dat3 <- reshape(data, direction="long",
varying = list(c("SURVEY_YEAR","REFERENCE_YEAR"), c("CUMULATIVE_SUM","CUMULATIVE_SUM_REFYEAR")),
v.names=c("YEAR","CUMULATIVE_SUM"), times = c("SURVEY_YEAR", "REFERENCE_YEAR"))
有谁知道如何正确重塑数据框，使其与上面所需的解决方案相对应？谢谢。
只需重新排序您已有的数据
dat3 <- dat3[with(dat3, order(NAME, ID, YEAR, id)), ]
或者如果您想要高性能
library(data.table)
setkey(setDT(dat3), NAME, ID, YEAR, id)
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句