我对此功能有疑问:
var url = "";
function multiSearchTest() {
var formData = $("#frmSearch").serialize();
var look = new Array("SDO", "AR", "AS", "AC", "AP", "GEMO", "CC");
var count;
for(count = 0; count < look.length; count++){
url = "index.php?Page&module=mod_page&action=dispatch&todo=cerca"+look[count]+"&" + formData;
console.log(url);
var test = "#"+look[count]+"result";
$.get(url, function(data) {
$(test).html(data);
console.log("TEST VAL => " + test);
});
}
}
如您所见,URL构造是完美的...但是当我说要在哪里打印输出时,它仅返回数组的最后一个val。有什么想法或建议吗?我的错误在哪里?
var test
在外面声明forloop
。并使其成为array.because,因为var test
在for loop
每次创建新对象时都在,因此在for循环外部声明变量test
function multiSearchTest() {
var formData = $("#frmSearch").serialize();
var look = new Array("SDO", "AR", "AS", "AC", "AP", "GEMO", "CC");
var count;
var test = [];
for(count = 0; count < look.length; count++){
url = "index.php?Page&module=mod_page&action=dispatch&todo=cerca"+look[count]+"&" + formData;
console.log(url);
test[count] = "#"+look[count]+"result";
$.get(url, function(data) {
$(test[count]).html(data);
console.log("TEST VAL => " + test[count]);
});
}
}
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