我不了解此错误或其含义。我将代码粘贴在下面,但是我认为它并不重要。我只想了解这个错误。
将所有数字1到1000(包括1和1000)中的字母加起来只是一点代码
def number_translator(x):
if x == 1:
return 3
elif x == 2:
return 3
elif x == 3:
return 5
elif x == 4:
return 4
elif x == 5:
return 4
elif x == 6:
return 3
elif x == 7:
return 5
elif x == 8:
return 5
elif x == 9:
return 4
elif x == 10:
return 3
elif x == 11:
return 6
elif x == 12:
return 6
elif x == 14:
return 8
elif x == 15:
return 7
elif x == 16:
return 7
elif x == 17:
return 9
elif x == 18:
return 8
elif x == 19:
return 8
elif x == 20:
return 6
elif x == 30:
return 6
elif x == 40:
return 5
elif x == 50:
return 5
elif x == 60:
return 5
elif x == 70:
return 7
elif x == 80:
return 6
elif x == 90:
return 6
count = 0
for element in range(1, 1001):
if element < 21:
count += number_translator(element) # for numbers 1 - 20
elif 20 < element < 100:
count += number_translator(int(str(element)[0]) * 10) + number_translator(int(str(element)[1])) # for numbers 21 through 100
elif element % 100 == 0 and element != 1000:
count += number_translator(int(str(element)[0])) + 7 # for numbers divisible by 100, but not 1000
elif element == 1000:
count += 11 # just for 1000
elif element % 100 < 20:
count += number_translator(int(str(element)[0])) + 10 + number_translator(int(str(element)[1:3])) # now I add in numbers like 101 - 120, 201 - 220, etc.
else:
count += number_translator(int(str(element)[0])) + 10 + number_translator(int(str(element)[1]) * 10) + number_translator(int(str(element)[2])) # now the rest( 121, 122, 123, 225, 256, 984, etc.)
print(count)
当所有if
测试都不number_translator()
为true时,该函数返回None
。该错误消息是其结果。
每当看到包含以下内容的错误时,'NoneType'
这意味着您有一个操作数或一个对象,而该对象正是None
您期望其他事物的时候。
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句