启动额外的perl模块中定义的子例程的线程的正确语法是什么?
perl程序:
use strict;
use warnings;
use forks;
require testModule;
# before solution - thanks ysth!
# testModule->main will not work!
#my $thr1 = threads->new(\&testModule->main, "inputA_1", "inputB_1");
#my $thr2 = threads->new(\&testModule->main, "inputA_2", "inputB_2");
# solved
#my $thr1 = threads->new(\&testModule::main, "inputA_1", "inputB_1");
#my $thr2 = threads->new(\&testModule::main, "inputA_2", "inputB_2");
my @output1 = $thr1->join;
my @output2 = $thr2->join;
perl模块testModule.pm:
package testModule;
sub main{
my @input = @_;
#some code
return ($output1, $output2)
}
testModule-> main的确切系统调用是什么?
提前致谢!
您几乎完全正确:
...threads->new( \&testModule::main, "inputA_1", "inputB_1" );
->
仅用于类/实例方法调用;如果您希望将其作为类方法调用(它将@input
获得类名以及“ inputA_1”和“ inputB_1”),则可以执行以下操作:
...threads->new( sub { testModule->main(@_) }, "inputA_1", "inputB_1" );
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