自动滚动到HorizontalScrollView

DmRomantsov的答案是滚动到第12个按钮的正确方法。但是，由于布局尚未显示在屏幕上，getLeft()因此getRight()方法会返回0。现在计算父级和子级布局的宽度还为时过早。为此，您需要在中进行自动滚动onWindowFocusChanged。

@Override
public void onWindowFocusChanged(boolean hasFocus){
    super.onWindowFocusChanged(hasFocus);
    if(hasFocus){
        // do smoothScrollTo(...);
    }
} 

但是，在Fragment内部，上述方法无效。我只是写了一个线索，以了解概念。要在Fragment中具有相同的行为，您只需要执行一项操作Runnable即可显示UI时间。然后，使用LinearLayout水平方向进行此操作：

// Init variables
HorizontalScrollView mHS;
LinearLayout mLL;  

// onCreateView method
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.layout_container, container, false);

    // Find your views
    mHS = (HorizontalScrollView)view.findViewById(R.id.hscrollview);
    mLL = (LinearLayout)view.findViewById(R.id.hscrollview_container);  

    // Do a Runnable on the inflated view
    view.post(new Runnable() {
        @Override
        public void run() {
            Log.v("","Left position of 12th child = "+mLL.getChildAt(11).getLeft());
            mHS.smoothScrollTo(mLL.getChildAt(11).getLeft(), 0);
        }
    });
    return view;
}

中间Horizo​​ntalScrollView：

您的问题是自动滚动直到您的第12个孩子。但是，在下面的评论中，您要求我在HorizontalScrollView假设在每台设备上的中间进行自动滚动。您需要计算屏幕的宽度，容器的总宽度以及设备宽度内显示的子代数。这是一个简单的代码：

// Auto scroll to the middle (regardless of the width screen)
view.post(new Runnable() {
    @Override
    public void run() {
        // Width of the screen
        DisplayMetrics metrics = getActivity().getResources()
                                 .getDisplayMetrics();
        int widthScreen = metrics.widthPixels;
        Log.v("","Width screen total = " + widthScreen);

        // Width of the container (LinearLayout)
        int widthContainer = mLL.getWidth();
        Log.v("","Width container total = " + widthContainer );

        // Width of one child (Button)
        int widthChild = mLL.getChildAt(0).getWidth();
        Log.v("","Width child = " + widthChild);

        // Nb children in screen    
        int nbChildInScreen = widthScreen / widthChild;
        Log.v("","Width screen total / Width child = " + nbChildInScreen);

        // Width total of the space outside the screen / 2 (= left position)
        int positionLeftWidth = (widthContainer 
                                - (widthChild * nbChildInScreen))/2;
        Log.v("","Position left to the middle = " + positionLeftWidth);

        // Auto scroll to the middle
        mHS.smoothScrollTo(positionLeftWidth, 0);

    }
});

/** 
  * Your value might be resumed by:
  *
  * int positionLeftWidth = 
  *       ( mLL.getWidth() - ( mLL.getChildAt(0).getWidth() * 
  *       ( metrics.widthPixels / mLL.getChildAt(0).getWidth() ) ) ) / 2;  
  *
**/

具有选定值的中间Horizo​​ntalScrollView：

我有点误解了真正的要求。实际上，您想自动滚动到选定的子视图，然后在屏幕中间显示该视图。
然后，我改变了最后int positionLeftWidth现在是指所选择的视图相对于其父的左侧位置，包含在一个画面孩子的数量，以及所选择的视图的半值宽度。因此，代码与上面相同，除了positionLeftWidth：

// For example the chosen value is 7

// 7th Child position left    
int positionChildAt = mLL.getChildAt(6).getLeft();

// Width total of the auto-scroll (positionLeftWidth)
int positionLeftWidth = positionChildAt - // position 7th child from left less
                ( ( nbChildInScreen    // ( how many child contained in screen
                  * widthChild ) / 2 ) // multiplied by their width ) divide by 2
                + ( widthChild / 2 );  // plus ( the child view divide by 2 )

// Auto-scroll to the 7th child
mHS.smoothScrollTo(positionLeftWidth, 0);  

然后，无论getChildAt()方法中的值如何，以及屏幕的宽度如何，您总是会在屏幕中间找到（在您的情况下）选择的按钮。