只是想弄清楚为什么这段代码返回分段错误。Gdb说的那行给了我strcpy(newNode -> data -> ticket_name, name);功能上说的错误strcat()。有任何想法吗？我还要指出，我是C语言的新手。
void add_ticket(tm_type * tm)
{
char name[TICKET_NAME_LEN+1], type, zone[TICKET_ZONE_LEN], buffer[5], *ptr, *pos;
int price;
BOOLEAN check = TRUE;
printf("Add Ticket\n");
printf("----------\n");
printf("\n");
printf("Ticket name (1-40 characters): ");
if(fgets(name, sizeof(name), stdin) != NULL){
if(name[0] != '\n'){
if((pos=strchr(name, '\n')) != NULL){
*pos = '\0';
}
printf("\nTicket type (1 character): ");
type = fgetc(stdin);
if(type != '\n'){
read_rest_of_line();
printf("\nTicket zone (1-3 characters): ");
if(fgets(zone, sizeof(zone), stdin) != NULL){
if(zone[0] != '\n'){
if((pos=strchr(zone, '\n')) != NULL){
*pos = '\0';
}
printf("\n\n");
printf("Price (in cents): ");
if(fgets(buffer, sizeof(buffer), stdin) != NULL){
price = strtol(buffer, &ptr, 10);
if(buffer[0] != '\n'){
//create new node
stock_node *newNode = (stock_node*)malloc(sizeof(stock_node));
if(newNode == NULL){
fprintf(stderr, "Unable to allocate memory for new ticket.\n");
exit(EXIT_FAILURE);
}
strcpy(newNode -> data -> ticket_name, name);
newNode -> data -> ticket_type = type;
strcpy(newNode -> data -> ticket_zone, zone);
newNode -> data -> ticket_price = price;
newNode -> data -> stock_level = DEFAULT_STOCK_LEVEL;
newNode -> next_node = NULL;
//check for first insertion
if(tm -> stock -> head_stock -> next_node == NULL){
tm -> stock -> head_stock -> next_node = newNode;
printf("First ticket added.\n");
}
else{
//else loop through the list and find the last
//node, insert next to it
stock_node *stream = tm -> stock -> head_stock;
while(check == TRUE){
if(stream -> next_node == NULL){
stream -> next_node = newNode;
printf("Ticket added.\n");
check = FALSE;
}
stream = stream -> next_node;
}
}
}
}
}
}
}
}
}
}
您为分配了空间newNode，但从未进行任何初始化。因为newNode -> data其中包含垃圾，所以当您使用第二个箭头取消引用它时，您会遇到段错误。我的c生锈了，但是我相信你想要
// create new node
stock_node *newNode = (stock_node*)malloc(sizeof(stock_node));
newNode -> data = (data_struct*)malloc(sizeof(data_struct));
...
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句