mysql：截断一个字段并聚合另一个表中的数据

我有一个表，该表具有日期时间形式的日期。

mysql> select * from topsmsspammers_hour limit 1;
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| date                | spam | suspect | clean | spammer      | spam_campaign_id                            | messageType | policy | isSenderPolicy |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| 2013-06-11 23:00:00 |    1 |       0 |     0 | +12073708065 | NotSet|Message35392HerbisReallyWorkingRealy |           4 |      1 |              1 |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
1 row in set (0.00 sec)

mysql>

我想使用此表中的数据来填充具有完全相同的列名但日期被截断（且更改为反映更改的计数）的合计日期日期表，我首先确定了将截断我需要的数据的选择查询：

mysql> select SUBSTRING_INDEX(date, ' ', 1) as date, sum(spam) as spam, sum(suspect) as suspect, sum(clean) as clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy from topsmsspammers_hour group by date, spammer, spam_campaign_id, messageType, policy, isSenderPolicy limit 1;
+------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| date       | spam | suspect | clean | spammer      | spam_campaign_id                            | messageType | policy | isSenderPolicy |
+------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| 2013-06-11 |    1 |       0 |     0 | +12073708065 | NotSet|Message35392HerbisReallyWorkingRealy |           4 |      1 |              1 |
+------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
1 row in set, 1 warning (1.66 sec)

mysql>

然后，我尝试使用该选择查询来填充新表，但未插入截断的日期。而是插入了原始日期：

mysql> insert into topsmsspammers_day (date, spam, suspect, clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy) select SUBSTRING_INDEX(date, ' ', 1) as date, sum(spam) as spam, sum(suspect) as suspect, sum(clean) as clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy from topsmsspammers_hour group by date, spammer, spam_campaign_id, messageType, policy, isSenderPolicy limit 1;
Query OK, 1 row affected, 1 warning (1.68 sec)
Records: 1  Duplicates: 0  Warnings: 1

mysql> select * from topsmsspammers_day limit 1;                                                                +---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| date                | spam | suspect | clean | spammer      | spam_campaign_id                            | messageType | policy | isSenderPolicy |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| 2013-06-11 00:00:00 |    1 |       0 |     0 | +12073708065 | NotSet|Message35392HerbisReallyWorkingRealy |           4 |      1 |              1 |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
1 row in set (0.00 sec)

mysql>

我尝试然后更改数据以使用不同的名称来填充新表，但这仍然导致将完整日期插入到表中：

mysql> insert into topsmsspammers_day (date, spam, suspect, clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy) select SUBSTRING_INDEX(date, ' ', 1) as dayDate, sum(spam) as spam, sum(suspect) as suspect, sum(clean) as clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy from topsmsspammers_hour group by dayDate, spammer, spam_campaign_id, messageType, policy, isSenderPolicy limit 1;
Query OK, 1 row affected (1.75 sec)
Records: 1  Duplicates: 0  Warnings: 0

mysql> select * from topsmsspammers_day limit 1;
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| date                | spam | suspect | clean | spammer      | spam_campaign_id                            | messageType | policy | isSenderPolicy |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
| 2013-06-11 00:00:00 |    1 |       0 |     0 | +12073708065 | NotSet|Message35392HerbisReallyWorkingRealy |           4 |      1 |              1 |
+---------------------+------+---------+-------+--------------+---------------------------------------------+-------------+--------+----------------+
1 row in set (0.00 sec)

mysql>

我什至尝试更改插入内容中的名称，但由于名称不是新表中的字段，因此失败了：

mysql> insert into topsmsspammers_day (dayDate, spam, suspect, clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy) select SUBSTRING_INDEX(date, ' ', 1) as dayDate, sum(spam) as spam, sum(suspect) as suspect, sum(clean) as clean, spammer, spam_campaign_id, messageType, policy, isSenderPolicy from topsmsspammers_hour group by dayDate, spammer, spam_campaign_id, messageType, policy, isSenderPolicy limit 1;
ERROR 1054 (42S22): Unknown column 'dayDate' in 'field list'
mysql>

我想念什么？如何将截断的聚合数据插入到新表中？

一种

看起来好像2013-06-11 23:00:00已更改为2013-06-11 00:00:00，所以dataType A可能存在问题