我在使用SQL查询时遇到问题...我有一个导出CSV文件的文件,该文件在我向查询添加约束之前一直有效。
这是我所拥有的
<?php
$today = date("mdY");
function exportMysqlToCsv($table,$filename = 'TodaysSubmissions.csv')
{
$csv_terminated = "\n";
$csv_separator = ",";
$csv_enclosed = '"';
$csv_escaped = "\\";
$sql_query = "SELECT * FROM $table WHERE submitDate = '".$today."'";
我想仅从今天开始导出所有记录,并且在我的表单中我为$ today使用相同的日期格式,因此它应该匹配。
另外,当我更改为它时,它会按照我想要的方式完全创建CSV文件
$sql_query = "SELECT * FROM $table WHERE submitDate = 08142013";
那么,当我在查询中调用$ today时,我在做什么错呢?我觉得我已经尝试了所有可能的方法。
在这里编辑是整个文件
$today = date("mdY");
function exportMysqlToCsv($table,$filename = 'TodaysSubmissions.csv')
{
$csv_terminated = "\n";
$csv_separator = ",";
$csv_enclosed = '"';
$csv_escaped = "\\";
$sql_query = 'SELECT * FROM $table WHERE submitDate = "'.$today.'"';
// Gets the data from the database
$result = mysql_query($sql_query);
$fields_cnt = mysql_num_fields($result);
$schema_insert = '';
for ($i = 0; $i < $fields_cnt; $i++)
{
$l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
$schema_insert .= $l;
$schema_insert .= $csv_separator;
} // end for
$out = trim(substr($schema_insert, 0, -1));
$out .= $csv_terminated;
// Format the data
while ($row = mysql_fetch_array($result))
{
$schema_insert = '';
for ($j = 0; $j < $fields_cnt; $j++)
{
if ($row[$j] == '0' || $row[$j] != '')
{
if ($csv_enclosed == '')
{
$schema_insert .= $row[$j];
} else
{
$schema_insert .= $csv_enclosed .
str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
}
} else
{
$schema_insert .= '';
}
if ($j < $fields_cnt - 1)
{
$schema_insert .= $csv_separator;
}
} // end for
$out .= $schema_insert;
$out .= $csv_terminated;
} // end while
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header("Content-Length: " . strlen($out));
// Output to browser with appropriate mime type, you choose ;)
header("Content-type: text/x-csv");
//header("Content-type: text/csv");
//header("Content-type: application/csv");
header("Content-Disposition: attachment; filename=$filename");
echo $out;
exit;
如果您想让$today
变量可用于所有函数,并在函数外部声明它,则必须使用global
以下命令在函数内部声明它:
<?php
$today = date("mdY");
...
function exportMysqlToCsv($table,$filename = 'TodaysSubmissions.csv')
{
global $today;
...
$sql_query = "SELECT * FROM $table WHERE submitDate = '".$today."'";
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另外你在“全”的代码有这样的:
$sql_query = 'SELECT * FROM $table WHERE submitDate = "'.$today.'"';
可以肯定,双引号不起作用。
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