我非常new想与block_id进行Node JS比较following arrays。如果arrayBblock_id与block_id匹配，arrayA则添加新属性isExist：true，否则返回false
var arrayB = [{ "block_id": 1 },{ "block_id": 3 }];
const arrayA = [
{
"block_id": 1,
"block_name": "test 1",
"children": [
{
"block_id": 2,
"block_name": "test 2",
"children": [
{
"block_id": 3,
"block_name": "test 2",
}
]
}
],
}
]
尝试以下代码进行比较
const result = arrayA.map(itemA => {
return arrayB
.filter(itemB => itemB.block_id === itemA.block_id)
.reduce((combo, item) => ({...combo, ...item}), {isExist: true})
});
我正在关注
输出
[ { isExist: true, block_id: 1 } ]
预期的
[
{
"block_id": 1,
"block_name": "test 1",
"isExist": true,
"children": [
{
"block_id": 2,
"block_name": "test 2",
"isExist": false,
"children": [
{
"block_id": 3,
"block_name": "test 2",
"isExist": true,
}
]
}
],
}
];
此函数是递归函数，因此您也可以遍历子级。
function procesArray(arr, arrayB) {
return arr.reduce((result, item) => {
const itemInB = arrayB.find(itemB => itemB.block_id == item.block_id)
if (itemInB)
item.isExist = true;
if (item.children)
procesArray(item.children, arrayB);
return [...result, item];
}, [])
}
现在，您可以像这样调用函数
const result = procesArray(arrayA, arrayB);
result 将如下
[{
"block_id": 1,
"block_name": "test 1",
"children": [{
"block_id": 2,
"block_name": "test 2",
"children": [{
"block_id": 3,
"block_name": "test 2",
"isExist": true
}]
}],
"isExist": true
}]
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