如何在Spring Integration(Java DSL)中为完整流程定义事务?
通过Spring集成,我们可以定义一个示例流程,其中包括:
@Bean
public IntegrationFlow myMessageFromMessageAmqpInboundFlow() {
return IntegrationFlows.from(myInboundChannel)
.transform(aMessageTransformer)
.transform(anotherMessageTransformer)
.channel(anOutputChannel)
.get();
}
我需要一项能够覆盖整个流程的交易。当前,当我使用“ aMessageTransformer”访问数据库时,在处理了此消息转换器之后,事务将关闭。但是我需要一个在处理“ anotherMessageTransformer”时仍未提交的事务吗?
我希望我只需要添加一个'@Transactional'(或@Transactional(propagation = Propagation.REQUIRED,readOnly = true))
@Bean
@Transactional
public IntegrationFlow myMessageFromMessageAmqpInboundFlow() {
return IntegrationFlows.from(myInboundChannel)
.transform(aMessageTransformer)
.transform(anotherMessageTransformer)
.channel(anOutputChannel)
.get();
}
但这会导致“ anotherMessageTransformer”中出现“无会话异常”
您需要遵循以下文档,因此将其添加到您的流程中:
.transform(aMessageTransformer, e -> e.transactional(true))
这.transactional()
是关于:
/**
* Specify a {@link TransactionInterceptor} {@link Advice} with default
* {@code PlatformTransactionManager} and {@link DefaultTransactionAttribute} for the
* {@link MessageHandler}.
* @param handleMessageAdvice the flag to indicate the target {@link Advice} type:
* {@code false} - regular {@link TransactionInterceptor}; {@code true} -
* {@link org.springframework.integration.transaction.TransactionHandleMessageAdvice}
* extension.
* @return the spec.
*/
public S transactional(boolean handleMessageAdvice) {
该TransactionHandleMessageAdvice
方式:
* When this {@link Advice} is used from the {@code request-handler-advice-chain}, it is applied
* to the {@link MessageHandler#handleMessage}
* (not to the
* {@link org.springframework.integration.handler.AbstractReplyProducingMessageHandler.RequestHandler#handleRequestMessage}),
* therefore the entire downstream process is wrapped to the transaction.
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我来说两句