我需要一个唯一的结果,从tableB.Field到tableA.Field我正在使用sdo运算符sdo_nn,这是代码:
UPDATE table1 t1
SET t1.fieldA = (SELECT T2.fieldB,SDO_NN_DISTANCE(1) distance
FROM table1 T1, table2 T2
WHERE
(sdo_nn(t1.geometry,t2.geometry,'SDO_NUM_RES=1',1)= 'TRUE')
ORDER BY DIST
)
WHERE EXISTS(
SELECT 1
FROM table2 t2
WHERE sdo_nn(t1.geometry, t2.geometry,'SDO_NUM_RES=1',1)='TRUE'
AND(t2.cell_name = 'string1' or t2.cell_name = string2')AND t1.fieldA = NULL
);
在子查询的选择语句中,我得到一个错误,因为我仅使用一个字段(t1.fieldA),但是在语句中,我使用了运算符SDO_NN_DISTANCE(1),而sql开发人员像另一个字段一样对这个运算符进行计数。写这句话的正确方法是什么?我只使用sql,因为我需要在vba中插入此代码
谢谢!!!
显然,您不能(简化)
set t1.fieldA = (t2.fieldB, distance) --> you want to put two values into a single column
因此,请fieldB
从使用解析函数(row_number
)对行进行“排序”的子查询中单独获取sdo_nn_distance(1) desc
;然后获取第一行的fieldB
值。
这样的事情(我希望我设置正确的括号):
UPDATE table1 t1
SET t1.fieldA =
(SELECT x.fieldB --> only fieldB
FROM (SELECT T2.fieldB, --> from your subquery
SDO_NN_DISTANCE (1) distance,
ROW_NUMBER ()
OVER (ORDER BY sdo_nn_distance (1) DESC) rn
FROM table1 T1, table2 T2
WHERE (sdo_nn (t1.geometry,
t2.geometry,
'SDO_NUM_RES=1',
1) = 'TRUE')) x
WHERE rn = 1) --> where RN = 1
WHERE EXISTS
(SELECT 1
FROM table2 t2
WHERE sdo_nn (t1.geometry,
t2.geometry,
'SDO_NUM_RES=1',
1) = 'TRUE'
AND ( t2.cell_name = 'string1'
OR t2.cell_name = 'string2')
AND t1.fieldA IS NULL);
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