//Square root of a no. using command line argument
class Calculator {
double i;
double x = Math.sqrt(i);
}
class SquareRoot {
public static void main(String arg[]) {
Calculator a = new Calculator();
a.i = Integer.parseInt(arg[0]);
System.out.println("The square root of " + a.i + " is " + a.x);
}
}
我的输出：
The square root of 64 is 0.0
我的代码有什么问题？
试试这个 ：
class Calculator {
double i, x;
void squareRoot() {
x = Math.sqrt(i);
}
}
class SquareRoot {
public static void main(String arg[]) {
Calculator a = new Calculator();
a.i = Integer.parseInt(arg[0]);
a.squareRoot();
System.out.println("The square root of " + a.i + " is " + a.x);
}
}
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