我有一个有关链表的项目,但是很难。老师要我阅读.txt文件并从中创建单链接列表。之后,我需要反转每行的奇数。然后打印。这是我用于打印链表的代码。但是我需要帮助反转每行的奇数。
这是我用来打印列表的代码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct list {
char *string;
struct list *next;
};
typedef struct list LIST;
int main(void) {
FILE *fp;
char line[10];
LIST *current, *head;
head = current = NULL;
fp = fopen("data.txt", "r");
while(fgets(line, sizeof(line), fp)){
LIST *node = malloc(sizeof(LIST));
node->string = strdup(line);
node->next =NULL;
if(head == NULL){
current = head = node;
} else {
current = current->next = node;
}
}
fclose(fp);
for(current = head; current ; current=current->next){
printf("%s", current->string);
}
return 0;
}
这是.txt文件的内容:
10
9,6,11,7,12,18,19,14,15,13
13,14,9,12,15,3,18,20,1,2
4,11,8,17,12,15,20,10,3,16
19,4,11,1,13,17,12,16,20,18
1,6,20,11,13,9,7,16,10,2
12,4,11,16,3,20,9,19,17,15
20,3,10,12,18,2,5,14,15,16
18,19,15,2,6,9,1,3,17,4
7,6,20,1,11,4,3,5,8,16
1,2,16,13,17,10,12,9,4,15
希望这段代码能完成这项工作。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct line {
struct num *first;
struct line *next;
} LineNode;
typedef struct num {
int num;
int order;
struct num *next;
} NumNode;
int main() {
FILE *fp;
char ch;
int counter = 0;
NumNode *curr_num, *even_ptr, *odd_ptr, *odd_head, *even_head;
LineNode *curr_line, *line_head;
curr_num = even_head = odd_head = even_ptr = odd_ptr = NULL;
line_head = curr_line = NULL;
fp = fopen("data.txt", "r");
if (fp == NULL)
{
return 1;
}
ch = fgetc(fp);
while(ch != EOF){
if (ch >= 48 && ch <= 57)
{
int n = 0;
while (ch != EOF && ch != '\n' && ch >= 48 && ch <= 57)
{
int x = ch - 48;
n = n * 10 + x;
ch = fgetc(fp);
}
NumNode *node = malloc(sizeof(NumNode));
node->num = n;
node->order = counter;
node->next =NULL;
if (n % 2 == 0){
if(even_head == NULL){
even_head = even_ptr = node;
} else {
even_ptr = even_ptr->next = node;
}
}else{
if(odd_head == NULL){
odd_head = node;
} else {
node->next = odd_head;
odd_head = node;
}
}
counter++;
}
if (ch == '\n' || ch == EOF)
{
NumNode *num_node, *head;
num_node = head = NULL;
even_ptr = even_head;
odd_ptr = odd_head;
counter = 0;
if (even_head != NULL && even_head->order == counter){
head = num_node = even_ptr;
even_ptr = even_ptr->next;
} else {
head = num_node = odd_ptr;
odd_ptr = odd_ptr->next;
}
counter++;
while (even_ptr != NULL)
{
if (even_ptr->order == counter) {
num_node = num_node->next = even_ptr;
even_ptr = even_ptr->next;
}
else if (odd_ptr != NULL) {
num_node = num_node->next = odd_ptr;
odd_ptr = odd_ptr->next;
}
counter++;
}
while (odd_ptr != NULL)
{
num_node = num_node->next = odd_ptr;
odd_ptr = odd_ptr->next;
}
LineNode *node = malloc(sizeof(LineNode));
node->next =NULL;
node->first = head;
if (line_head == NULL)
line_head = curr_line = node;
else
curr_line = curr_line->next = node;
odd_head = even_head = NULL;
counter = 0;
}
ch = fgetc(fp);
}
fclose(fp);
for(curr_line = line_head; curr_line != NULL ; curr_line=curr_line->next) {
for(curr_num = curr_line->first; curr_num != NULL ; curr_num=curr_num->next) {
printf("%d", curr_num->num);
if (curr_num->next != NULL)
printf(",");
}
printf("\n");
}
return 0;
}
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句