我是Python的新手。我有一个成员列表和一个会议列表（包含成员ID）：
memberList = [{'id': '1', 'name': 'Joe'},
{'id': '2', 'name': 'Jason'},
{'id': '3', 'name': 'Billy'}]
meetingList = [{'meetingId': '20', 'hostId' : '1'},
{'meetingId': '21', 'hostId' : '1'},
{'meetingId': '22', 'hostId' : '2'},
{'meetingId': '23', 'hostId' : '2'}]
成员的id和会议的hostId的值相同。
结果：没有会议的成员ID['3']列表或词典列表[{'id': '3', 'name': 'Billy'}]
最佳和最易读的方法是什么？
member_list = [{'id': '1', 'name': 'Joe'},
{'id': '2', 'name': 'Jason'},
{'id': '3', 'name': 'Billy'}]
meeting_list = [{'meetingId': '20', 'hostId': '1'},
{'meetingId': '21', 'hostId': '1'},
{'meetingId': '22', 'hostId': '2'},
{'meetingId': '23', 'hostId': '2'}]
# create a set of hosts
hosts = set(meeting['hostId'] for meeting in meeting_list) # or { meeting['hostId'] for meeting in meeting_list }
# filter out the members that are in hosts
res = [member['id'] for member in member_list if member['id'] not in hosts]
print(res)
输出量
[{'id': '3', 'name': 'Billy'}]
对于仅id输出，请执行以下操作：
res = [member['id'] for member in member_list if member['id'] not in hosts]
print(res)
输出量
['3']
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