如何将多个值添加到密钥字典

BOWS 发表于 Dev

弓箭

我有一个franco-france文件，我希望以年为关键，而其他信息为值。

文件的一部分看起来像这样

Year,Cyclist,Time,Distance,Hours,Minutes,Seconds,Team,CyclistNumber,TotalSeconds,Gap,Stages
1903,MAURICE GARIN,94h 33' 14'',2428,94,33,14,TDF 1903 ***,1,340394,-,6
1903,LUCIEN POTHIER,97h 32' 35'',2428,97,32,35,TDF 1903 ***,37,351155,+ 02h 59' 21'',6
1903,FERNAND AUGEREAU,99h 02' 38'',2428,99,2,38,TDF 1903 ***,39,356558,+ 04h 29' 24'',6
1903,RODOLPHE MULLER,99h 12' 44'',2428,99,12,44,TDF 1903 ***,33,357164,+ 04h 39' 30'',6
1903,JEAN-BAPTISTE FISCHER,99h 41' 58'',2428,99,41,58,TDF 1903 ***,12,358918,+ 05h 08' 44'',6
1903,ARSENE MILLOCHEAU,155h 30' 44'',2428,155,30,44,TDF 1903 ***,67,559844,+ 60h 57' 30'',6

我做了以下字典

with open("tour-de-france.csv") as file:
    reader = csv.reader(file)
    no_header = next(reader, None)
    new_dct = {}
    for x in reader:
        new_dct[x[0]] = x[1:]
    print(new_dct)

部分输出如下所示：

{'1903': ['ARSENE MILLOCHEAU', "155h 30' 44''", '2428', '155', '30', '44', 'TDF 1903 ***', '67', '559844', "+ 60h 57' 30''", '6']

输出仅具有1903年的最后一个人作为值，但是是否也可以使1903年的每个人作为值？

Nilesh Soni

您可以使用列表列表作为值，即

with open("tour-de-france.csv") as file:
    reader = csv.reader(file)
    no_header = next(reader, None)
    new_dct = {}
    for x in reader:
        new_dict.setdefault(x[0], [])
        new_dct[x[0]].append(x[1:])
    print(new_dct)

这将导致这样的事情

{'1903': [['MAURICE GARIN', ...], ['LUCIEN POTHIER', ...], ['FERNAND AUGEREAU', ...], ['RODOLPHE MULLER', ...], ['JEAN-BAPTISTE FISCHER', ...] ['ARSENE MILLOCHEAU', "155h 30' 44''", '2428', '155', '30', '44', 'TDF 1903 ***', '67', '559844', "+ 60h 57' 30''", '6']]

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