我需要通过按下按钮来触发继电器，然后等待信号，然后释放继电器。在下面的示例代码中，该信号为b2。我是Python和Pi的新手，但是很开心！:)
import RPi.GPIO as GPIO
GPIO.setmode(GPIO.BCM)
from gpiozero import Button
from signal import pause
import time
def first_button():
print("First Pressed")
while True: #do stuff...
time.sleep(1)
print("waiting...")
def second_button():
print("Second Pressed")
b1 = Button(23)
b1.when_pressed = first_button
b2 = Button(24)
b2.when_pressed = second_button
pause()
当按钮调用的现有功能仍在运行时，如何检测按钮按下？
在此解决方案中，您只能打开和关闭输出
from gpiozero import Button
from signal import pause
import time
pin = #Set a pin
r = LED(pin)
b1 = Button(23)
b1.when_pressed = r.on
b2 = Button(24)
b2.when_pressed = r.off
pause()
这里一个线程开始做事：
from gpiozero import Button
from signal import pause
import time
import _thread
run = False
def do_stuff():
while run: #do stuff...
time.sleep(1)
print("waiting...")
def first_button():
global run
print("First Pressed")
run = True
_thread.start_new_thread(do_stuff)
def second_button():
global run
print("Second Pressed")
run = False
b1 = Button(23)
b1.when_pressed = first_button
b2 = Button(24)
b2.when_pressed = second_button
pause()
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我来说两句