diff两个数组，每个数组包含文件路径到第三个数组（用于删除）

詹姆斯·伊辛

在下面的功能中，您将看到有关解决该问题的几种尝试的注释；每次尝试都有一条注释，指出出了什么问题。在我的尝试之间，这里的另一个问题似乎是想解决问题的某些要素。同样，我添加了一条注释，指出应解决的问题。这时我的大脑很糊涂。我忽略的愚蠢简单的事情是什么？

function func_removeDestinationOrphans() { 
    readarray -d '' A_Destination_orphans < <( find "${directory_PMPRoot_destination}" -type f -print0 ) 
    for (( i = 0 ; i < ${#A_Destination_orphans[@]} ; i++ )) ; do 
        printf '%s\n' "→    ${A_Destination_orphans[${i}]}" # path to each track 
    done 
    printf '%b\n' "" 
    # https://stackoverflow.com/questions/2312762/compare-difference-of-two-arrays-in-bash 
    # echo ${Array1[@]} ${Array2[@]} | tr ' ' '\n' | sort | uniq -u ## original 
    # Array3=(`echo ${Array1[@]} ${Array2[@]} | tr ' ' '\n' | sort | uniq -u `) ## store in array 
    # A_Destination_orphans_diff=(`echo "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | tr ' ' '\n' | sort | uniq -u `) # drops file path after space 
    # printf "%s\0" "${Array1[@]}" "${Array2[@]}" | sort -z | uniq -zu ## newlines and white spaces 
    # A_Destination_orphans_diff=($( printf "%s\0" "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | sort -z | uniq -zu )) # throws warning and breaks at space but not newline 
    # printf '%s\n' "${Array1[@]}" "${Array2[@]}" | sort | uniq -u ## manage spaces 
    # A_Destination_orphans_diff=($( printf '%s\n' "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | sort | uniq -u )) # breaks at space and newline 
    # A_Destination_orphans_diff="($( printf '%s\n' "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | sort | uniq -u ))" # creates string surrounded by () 
    # A_Destination_orphans_diff=("$( printf '%s\n' "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | sort | uniq -u )") # creates string 
    # A_Destination_orphans_diff=($( printf '%s\n' ${A_Destination_dubUnders[@]} ${A_Destination_orphans[@]} | sort | uniq -u )) # drops file path after space 
    for (( i = 0 ; i < ${#A_Destination_orphans_diff[@]} ; i++ )) ; do 
        printf '%s\n' "→    ${A_Destination_orphans_diff[${i}]}" # path to each track 
    done 
    printf '%b\n' "" 
    for (( i = 0 ; i < ${#A_Destination_orphans_diff[@]} ; i++ )) ; do 
        echo # rm "${A_Destination_orphans_diff[i]}" 
    done 
    func_EnterToContinue 
}

詹姆斯·伊辛

这是经过修改的工作版本，这要感谢前两位受访者的建议（谢谢！）。

function func_removeDestinationOrphans() { 
    printf '%s\n' " →   Purge playlist orphans:  " "" 
    printf '%b\n' "First we will remove any files not present in your proposed playlist.  " 
    func_EnterToContinue 
    bash_version="$( bash --version | head -n1 | cut -d " " -f4 | cut -d "(" -f1 )" 
    if printf '%s\n' "4.4.0" "${bash_version}" | sort -V -C ; then 
        readarray -d '' A_Destination_orphans < <( find "${directory_PMPRoot_destination}" -type f -print0 ) # readarray or mapfile -d fails before bash 4.4.0 
        readarray -t -d '' A_Destination_orphans_diff < <( 
            printf "%s\0" "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | 
            sort -z | 
            uniq -zu 
        ) 
    else 
        while IFS=  read -r -d $'\0'; do 
            A_Destination_orphans+=( "$REPLY" ) 
        done < <( find "${directory_PMPRoot_destination}" -type f -print0 ) 
        IFS=$'\37' read -r -d '' -a A_Destination_orphans_diff < <( 
        printf "%s\0" "${A_Destination_dubUnders[@]}" "${A_Destination_dubUnders[@]}" "${A_Destination_orphans[@]}" | 
            sort -z | 
            uniq -zu | 
            xargs -0 printf '%s\37' 
        ) 
    fi 
    if [[ ! "${A_Destination_orphans_diff[*]}" = '' ]] ; then 
        for (( i = 0 ; i < ${#A_Destination_orphans_diff[@]} ; i++ )) ; do 
            rm "${A_Destination_orphans_diff[i]}" 
        done 
    fi 
}

如果您想查看整个Personal Music Player同步脚本，可以通过我的GitHub找到。

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