空手道-匹配2个JSON对象以获取值较少且缺少键的对象

用户名

我有2 json，如下所示：

* def first = [{"code":"00","name":"A","iconUrl":"https:env1.test.png"}, {"code":"01","name":"B"}, {"code":"03","name":"C","iconUrl":"https:env1.test.png"}, {"code":"02","name":"D"}]

* def second = [{"iconUrl":"https:env2.test.png", "code":"00","name":"A"}, {"code":"01","name":"B"}, {"iconUrl":"https:env2.test.png", "code":"03","name":"C"}, {"code":"02","name":"D"}]

我想比较2个json对象。所有对象都没有iconUrl，而那些包含url中env的区别的对象。

我尝试了以下方法：

* def first = [{"code":"00","name":"A","iconUrl":"https:env1.test.png"}, {"code":"01","name":"B"}, {"code":"03","name":"C","iconUrl":"https:env1.test.png"}, {"code":"02","name":"D"}]
    * def second = [{"iconUrl":"https:env2.test.png", "code":"00","name":"A"}, {"code":"01","name":"B"}, {"iconUrl":"https:env2.test.png", "code":"03","name":"C"}, {"code":"02","name":"D"}]
    * def size = second.length
    And print "     size: ", size
    * def fun = function(i){ if (second[i].iconUrl != '#null') second[i].iconUrl = '#string'}
    * def foo = karate.repeat(size, fun)
    * match first contains second

我的测试失败，因为数组对象不包含iconUrl。如何为不包含iconUrl的对象添加另一个条件？

彼得·托马斯

干得好：

* def fun = function(x){ if (x.iconUrl) x.iconUrl = x.iconUrl.replace('env2', 'env1'); return x }
* def secondFixed = karate.map(second, fun)
* match first == secondFixed

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