我正在尝试使用Python 3将本网站的表格从.csv文件中抓取到:2011-2012 NBA国家赛程
该表开始如下:
Revised Schedule Original Schedule
Date Time Game Net Time Game Net
Sun., 12/25/11 12 PM BOS (1) at NY (1) TNT 12 PM BOS (7) at NY (7) ESPN
Sun., 12/25/11 2:30 PM MIA (1) at DAL (1) ABC 2:30 PM MIA (8) at DAL (5) ABC
Sun., 12/25/11 5 PM CHI (1) at LAL (1) ABC 5 PM CHI (6) at LAL (9) ABC
Sun., 12/25/11 8 PM ORL (1) at OKC (1) ESPN no game no game no game
Sun., 12/25/11 10:30 PM LAC (1) at GS (1) ESPN no game no game no game
Tue., 12/27/11 8 PM BOS (2) at MIA (2) TNT no game no game no game
Tue., 12/27/11 10:30 PM UTA (1) at LAL (2) TNT no game no game no game
我只对前四列的修订时间表感兴趣。我想要的.csv文件中的输出如下所示:
我正在使用这些软件包:
import re
import requests
import pandas as pd
import numpy as np
from bs4 import BeautifulSoup
from itertools import groupby
这是我为匹配所需格式所做的代码:
df = pd.read_html("https://www.sportsmediawatch.com/2011/12/revised-2011-12-nba-national-tv-schedule/", header=0)[0]
revisedCols = ['Date'] + [ col for col in df.columns if 'Revised' in col ]
df = df[revisedCols]
df.columns = df.iloc[0,:]
df = df.iloc[1:,:].reset_index(drop=True)
# Format Date to m/d/y
df['Date'] = np.where(df.Date.str.startswith(('10/', '11/', '12/')), df.Date + ' 11', df.Date + ' 12')
df['Date']=pd.to_datetime(df['Date'])
df['Date']=df['Date'].dt.strftime('%m/%d/%Y')
# Split the Game column
df[['Away','Home']] = df.Game.str.split('at',expand=True)
# Final dataframe with desired columns
df = df[['Date','Time','Away','Home','Net']]
df.columns = ['Date', 'Time', 'Away', 'Home', 'Network']
print(df)
输出:
Date Time Away Home Network
0 12/25/2011 12 PM BOS (1) NY (1) TNT
1 12/25/2011 2:30 PM MIA (1) DAL (1) ABC
2 12/25/2011 5 PM CHI (1) LAL (1) ABC
3 12/25/2011 8 PM ORL (1) OKC (1) ESPN
4 12/25/2011 10:30 PM LAC (1) GS (1) ESPN
5 12/27/2011 8 PM BOS (2) MIA (2) TNT
6 12/27/2011 10:30 PM UTA (1) LAL (2) TNT
我注意到客队和主队列中的每个球队名称旁边都有(1),(2)等。如何实施刮板程序删除“客队”和“主场”列中每个队名旁边的(1),(2)等?
您可以str.replace
将括号和数字一起使用,str.strip
而且看起来在开始或结尾处都有一些空格:
df['Away'] = df['Away'].str.replace('\(\d*\)', '').str.strip()
df['Home'] = df['Home'].str.replace('\(\d*\)', '').str.strip()
print (df.head())
Date Time Away Home Network
0 12/25/2011 12 PM BOS NY TNT
1 12/25/2011 2:30 PM MIA DAL ABC
2 12/25/2011 5 PM CHI LAL ABC
3 12/25/2011 8 PM ORL OKC ESPN
4 12/25/2011 10:30 PM LAC GS ESPN
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