如何正确使用数据透视创建自定义列名称

我有一个数据框，其中包含多个按日期排序的因子值：

    date_and_time           date        hour    factor st0  st1     st2
0   2012-01-01 00:00:00     2012-01-01  0       PM25    69.4000     58.00000    51.60000
1   2012-01-01 00:00:00     2012-01-01  0       CO      1.3800      1.15714     1.06585
2   2012-01-01 01:00:00     2012-01-01  1       PM25    127.2000    77.33330    89.20000
3   2012-01-01 01:00:00     2012-01-01  1       CO      1.5800      1.57143     1.63169

我将如何获得：

    date_and_time           date        hour    PM25_st0  PM25_st1  PM25_st2 COst0  COst1   COst2
0   2012-01-01 00:00:00     2012-01-01  0       69.4000   58.0000   51.6000  1.3800 1.15714 1.06585
1   2012-01-01 01:00:00     2012-01-01  1       127.200   77.3333   89.2000  1.5800 1.57143 1.63169

基本上枢轴化并创建相应的列，首先我尝试这样做：

df_data = {
    'date_and_time': ['2012-01-01 00:00:00','2012-01-01 00:00:00','2012-01-01 01:00:00','2012-01-01 01:00:00' ],
    'date': ['2012-01-01','2012-01-01','2012-01-01','2012-01-01'],
    'hour':[0,0,1,1],
    'factor':['PM25','CO','PM25','CO'],
    'st0':[69.4000 ,1.3800,127.2000,1.5800],
    'st1':[58.00000,1.15714,77.33330,1.57143],
    'st2':[51.60000,1.06585,89.20000,1.63169]
}

df_test = pd.DataFrame(df_data, columns = ['date_and_time', 'date','hour','factor','st0','st1','st2'])



df_pivoted = pd.pivot_table(df_test,index=["date_and_time","date","hour"],columns=["factor"],values=["st0","st1","st2"])

并得到：

有没有一种方法可以按因子自定义列？