我有一个查询,其选择语句如下所示:
SELECT
CAST(p.date AS DATE) AS 'Date',
x.Month,
x.Version,
x.Value AS 'fcst',
CASE WHEN isholiday = 0
THEN ROW_NUMBER() OVER (PARTITION BY x.Department, x.Month, p.isholiday ORDER BY p.date)
ELSE 0
END AS 'Index'
输出如下:
Date Month Version fcst isholiday Index
2020-01-01 January 3plus9 3679 1 0
2020-01-02 January 3plus9 3679 0 1
2020-01-03 January 3plus9 3679 0 2
2020-01-04 January 3plus9 3679 1 0
2020-01-05 January 3plus9 3679 1 0
2020-01-06 January 3plus9 3679 0 3
2020-01-07 January 3plus9 3679 0 4
2020-01-08 January 3plus9 3679 0 5
2020-01-09 January 3plus9 3679 0 6
2020-01-10 January 3plus9 3679 0 7
2020-01-11 January 3plus9 3679 1 0
2020-01-12 January 3plus9 3679 1 0
2020-01-13 January 3plus9 3679 0 8
2020-01-14 January 3plus9 3679 0 9
2020-01-15 January 3plus9 3679 0 10
2020-01-16 January 3plus9 3679 0 11
2020-01-17 January 3plus9 3679 0 12
2020-01-18 January 3plus9 3679 1 0
2020-01-19 January 3plus9 3679 1 0
2020-01-20 January 3plus9 3679 0 13
索引列基于“ isHoliday”列。如case语句所示,在isHoliday = 1的每个点,索引显示0。相反,如果天<> 1,则我需要Index值显示为其上方的Index值。
例如,在日期= 1月4日和1月5日的行上,索引需要显示为2。我试图对case语句进行更改,但无法找到解决方案。
我认为您想要的累计数量为holiday = 0
:
select sum(case when isholiday = 0 then 1 else 0 end) over (partition by department, month order by date) as my_index
如果holiday
仅采用两个值,则可以简化为:
select sum(1 - isholiday) over (partition by department, month order by date) as my_index
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