我是vispy和计算机图形学的新手。我必须根据某个方程生成一个抛物面,其中心和参数根据用户输入而变化。我浏览了vispy文档和示例,并对软件包有了一些想法。
我需要生成的抛物面应该具有旋转对称性,如下图所示:
我得到的是这里
我的代码如下。我已经isosurface.py
在vispy示例中修改了示例。
import sys
import numpy as np
from vispy import app, scene
from matplotlib import pyplot as plt
# Create a canvas with a 3D viewport
canvas = scene.SceneCanvas(keys='interactive')
view = canvas.central_widget.add_view()
## Define a scalar field from which we will generate an isosurface
def psi3(i, j, k, offset=(25, 25, 25)):
x = i-offset[0]
y = j-offset[1]
z = k-offset[2]
r = (0.2*x**2 + 0.2*y**2 - 4*z)
return r
# Create isosurface visual
data = np.fromfunction(psi3, (50, 50, 50))
surface = scene.visuals.Isosurface(data, level=data.max() / 4., color=(0.5, 0.6, 1, 1), shading='smooth', parent=view.scene)
surface.transform = scene.transforms.STTransform(translate=(-25, -25, -25))
# Add a 3D axis to keep us oriented
axis = scene.visuals.XYZAxis(parent=view.scene)
# Use a 3D camera
# Manual bounds; Mesh visual does not provide bounds yet
# Note how you can set bounds before assigning the camera to the viewbox
cam = scene.TurntableCamera(elevation=30, azimuth=30)
cam.set_range((-10, 10), (-10, 10), (-10, 10))
view.camera = cam
if __name__ == '__main__':
canvas.show()
if sys.flags.interactive == 0:
app.run()
我的查询如下:
编辑:
这是matplotlib
用于生成所需抛物面的相应代码。我也可以在matplotlib中创建抛物面带。
import matplotlib.pyplot as plt
from matplotlib import cm
import numpy as np
# Create the surface
radius = 5
hole_radius = 4
# Generate the grid in cylindrical coordinates
r = np.linspace(0, radius, 100)
theta = np.linspace(0, 2 * np.pi, 100)
R, THETA = np.meshgrid(r, theta)
X, Y = R * np.cos(THETA), R * np.sin(THETA)
a=0.6;b=0.6;c=0.6
Z1 = (X/a)**2+(Y/b)**2 # Elliptic paraboloid
# Do not plot the inner region
x = np.where(X**2+Y**2<=hole_radius**2,np.NAN,X)
y = np.where(X**2+Y**2<=hole_radius**2,np.NAN,Y)
# Plot the surface
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_surface(x, y, Z1, cmap=cm.coolwarm, linewidth=0, antialiased=True, cstride=2, rstride=2)
ax.set_xlabel("X")
ax.set_ylabel("Y")
ax.set_zlabel("Z")
plt.show()
vispy和matplotlib的表面图之间的区别在于,后者通过接受x和y的2D数组来工作,而vispy的SurfacePlot()在x和y中仅接受一维向量。
由于网格为圆柱坐标并将其转换为直角坐标进行绘制,因此无法通过复制1D x和y向量来生成网格。
更新:正如@djhoesem所指出的,isosurface不是执行此操作的正确方法。
通过拉取请求添加了功能:https : //github.com/vispy/vispy/pull/1863#event-3344873987
对代码进行了少量修改并解决了该问题。
相应的示例可以在这里找到:https : //github.com/vispy/vispy/blob/master/examples/basics/visuals/axially_symmetric_surfaces.py
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句