我有一个对象数组。每个对象包含另一个内部数组。我想将每个内部数组作为外部对象，并将其余的旧外部元素作为新创建的外部对象的子属性。
输入值
data = [
{
name: "Sam",
ssn: 123,
age: 25,
hobbies: [{ name: "cricket" }, { name: "football" }]
},
{
name: "John",
ssn: 234,
age: 25,
hobbies: [{ name: "cricket" }, { name: "football" }]
},
{
name: "Mathew",
ssn: 345,
age: 25,
hobbies: [{ name: "cricket" }, { name: "football" }, {name: "carroms"}]
}
];
预期产量
[
{
name: "cricket",
person_details: [
{ name: "Sam", ssn: 123, age: 25 },
{ name: "John", ssn: 234, age: 25 },
{ name: "Mathew", ssn: 345, age: 25 }
]
},
{
name: "football",
person_details: [
{ name: "Sam", ssn: 123, age: 25 },
{ name: "John", ssn: 234, age: 25 },
{ name: "Mathew", ssn: 345, age: 25 }
]
},
{
name: "carroms",
person_details: [
{ name: "Mathew", ssn: 345, age: 25 }
]
}
]
我尝试使用减少尝试如下
this.data = this.data.reduce(
(a, x) => [...x.hobbies.map(h => ({ ...x, hobbies: [h] }))],
[]
);
您可以缩小数组并为结果集寻找相同的名称。
var data = [{ name: "Sam", ssn: 123, age: 25, hobbies: [{ name: "cricket" }, { name: "football" }] }, { name: "John", ssn: 234, age: 25, hobbies: [{ name: "cricket" }, { name: "football" }] }, { name: "Mathew", ssn: 345, age: 25, hobbies: [{ name: "cricket" }, { name: "football" }, { name: "carroms" }] }],
result = data.reduce((r, { hobbies, ...o }) => {
hobbies.forEach(({ name }) => {
var group = r.find(q => q.name === name);
if (!group) r.push(group = { name, person_details: [] });
group.person_details.push(o);
})
return r;
}, []);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }本文收集自互联网，转载请注明来源。
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