如何修改以下代码以避免嵌套Promises？
需要在Firestore中插入请求承诺的响应。
我还想知道当Firestore Promise解决将response.status发送给调用方应用程序时，如何使jsonresponse可用。
const functions = require('firebase-functions');
const rp = require('request-promise')
var admin = require("firebase-admin");
var serviceAccount = require("./service_key.json");
admin.initializeApp({
credential: admin.credential.cert(serviceAccount),
databaseURL: "https://melitest-5bc38.firebaseio.com"
});
let db = admin.firestore()
exports.customHttpRequest = functions.https.onRequest((request, response) => {
const url = 'https://jsonplaceholder.typicode.com/users'
var options = {
uri: url,
method: "GET",
json: true
};
rp(options).then((jsonresponse) => {
for(var i = 0 ; i < jsonresponse.length; i++){
var obj = jsonresponse[i]
var docid = obj.id
// Warning: Avoid nesting promises.eslint(promise/no-nesting)
db.collection("scrapeusertest").doc(String(docid)).set(obj).then(() =>{
console.log(`Data was upload to firestore and the response was: ${jsonresponse}`)
response.status(200).send(jsonresponse);
}).catch(error =>{
console.log(`Error uploading data Firebase: ${error}`)
});
}
return console.log("Data was send")
})
.catch((err) => {
console.log('Error:', err)
});
return null;
});
最简单的选择是使用异步功能：
const db = admin.firestore()
exports.customHttpRequest = functions.https.onRequest(async (request, response) => {
const url = 'https://jsonplaceholder.typicode.com/users'
const options = {
uri: url,
method: "GET",
json: true
};
const jsonresponse = await rp(options);
await Promise.all(jsonresponse.map(async obj => {
const docid = obj.id
try {
await db.collection("scrapeusertest").doc(String(docid)).set(obj);
} catch (error) {
console.log(`Error uploading data Firebase: ${error}`);
}
}));
console.log(`Data was upload to firestore and the response was: ${jsonresponse}`);
response.status(200).send(jsonresponse);
});
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