我正在尝试根据类似的列值联接表(A&B)||(C&D)
。我可以分别为A&B和C&D创建一个联接。但是我将如何完成OR
介于两者之间的条件?
[更新] A,B,C和D是dummy_level表中的level_id。因此,加入表的基本规则是(21 && 22)|| (23 && 24)
我的表结构是
CREATE TABLE dummy_cust(
id INT,
NAME VARCHAR(50),
age INT,
country VARCHAR(50));
INSERT INTO dummy_cust VALUES (1,'KIM',23,'US');
INSERT INTO dummy_cust VALUES (2,'KOM',24,'US');
INSERT INTO dummy_cust VALUES (3,'KING',29,'US');
INSERT INTO dummy_cust VALUES (4,'RAM',29,'US');
INSERT INTO dummy_cust VALUES (5,'RAV',23,'US');
INSERT INTO dummy_cust VALUES (6,'KIV',25,'US');
CREATE TABLE dummy_level(
id INT,
level_id INT,
STATUS VARCHAR(50));
INSERT INTO dummy_level VALUES (1,21,'C');
INSERT INTO dummy_level VALUES (1,22,'C');
INSERT INTO dummy_level VALUES (1,24,'C');
INSERT INTO dummy_level VALUES (2,22,'C');
INSERT INTO dummy_level VALUES (2,23,'C');
INSERT INTO dummy_level VALUES (2,24,'C');
INSERT INTO dummy_level VALUES (3,21,'Z');
INSERT INTO dummy_level VALUES (3,22,'Z');
INSERT INTO dummy_level VALUES (4,21,'Z');
INSERT INTO dummy_level VALUES (4,22,'Z');
INSERT INTO dummy_level VALUES (4,24,'Z');
预期结果:
+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +
| id | name | age | country | Level ID | Status | Level ID | Status | Level ID | Status | Level ID | Status |
+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +
| 1 | KIM | 23 | US | 21 | C | 22 | C | | | 24 | C |
| 2 | KOM | 24 | US | | | 22 | C | 23 | C | 24 | C |
| 3 | KING | 29 | US | 21 | Z | 22 | Z | | | | |
| 4 | RAM | 29 | US | 21 | Z | 22 | Z | | | 24 | Z |
+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +
请帮助解决此问题。由于我是新手,因此略有残障。我非常需要专家来帮助解决这一问题。
您正在使用一些值,所以最简单的方法是加入并使用pivot
:
select *
from dummy_cust c
join dummy_level l using (id)
pivot (max(level_id) lvl, max(status) sts
for level_id in (21 as l21, 22 as l22, 23 as l23, 24 as l24) )
order by id
如果我正确理解了您的评论,那么您希望在行级分别为21和22或级次为23和24时显示行。
select *
from (
select c.id, c.name, c.age, c.country, l.level_id, l.status,
count(case level_id when 21 then 1 end) over (partition by c.id) c21,
count(case level_id when 22 then 1 end) over (partition by c.id) c22,
count(case level_id when 23 then 1 end) over (partition by c.id) c23,
count(case level_id when 24 then 1 end) over (partition by c.id) c24
from dummy_cust c
join dummy_level l on c.id = l.id )
where (c21 > 0 and c22 > 0) or (c23 > 0 and c24 > 0)
然后,您可以进行演示。
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