我是新编码员。这是我的第一个python登录系统代码。如何简化我的代码而不会丢失任何功能，例如错误的用户名和错误的密码等？
username = "zaphod"
password = "helloworld42"
username2 = "mozzie"
password2 = "mozzietheaussie"
userUsername = input("Hello, What is your username? \n")
UserPassword = input(print("Hello", userUsername, "What is your password? "))
if userUsername == username:
if password == UserPassword:
print("Hello", userUsername, "Welcome home")
if userUsername == username:
if UserPassword != password:
print("Wrong Password")
if userUsername == username2:
if UserPassword != password2:
print("Wrong Password")
if UserPassword == password:
if userUsername != username:
print("Wrong Username")
if UserPassword == password2:
if userUsername != username2:
print("Wrong Username")
if userUsername == username2:
if UserPassword == password2:
print("Hello", userUsername,"Welcome Home")
if userUsername == username:
if UserPassword == password2:
print("Are you gonna trick me pal xd")
if userUsername == username2:
if UserPassword == password:
print("Are you gonna trick me pal xd")
if userUsername != username:
if userUsername != username2:
if UserPassword != password:
if UserPassword != password2:
print("Wrong credidentals")
您可以将凭据放在中，dict然后检查用户名是否存在并与密码匹配
credentials = {'zaphod': 'helloworld42',
'mozzie': 'mozzietheaussie'}
user_name = input('Hello, what is your username?\n')
password = input(f'Hello {user_name}, what is your password?\n')
pas = credentials.get(user_name) # returns None if the user name doesn't exists
if not pas:
print('Wrong Username')
elif pas != password:
print('Wrong Password')
else:
print(f'Hello {user_name}, welcome home')
在print("Are you gonna trick me pal xd")似乎是不必要的，但是你可以通过修改添加它elif
elif pas != password:
if password in credentials.values():
print('Are you gonna trick me pal xd')
else:
print('Wrong Password')
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