我试图返回两个范围内一组匹配项和不匹配项的总数。
我试图避免像这样循环两次遍历数组：
#expected output:
#inside: 421 | outside: 55
constant_range = 240..960
sample_range = 540..1015
sample_range_a = sample_range.to_a
def generate_range
inside = sample_range_a.select { |val| constant_range.include?(val) }.count
outside = sample_range_a.select { |val| !constant_range.include?(val) }.count
end
# I was thinking of a counter, but thought that would be even more ineffective
def generate_range
a = 0
b = 0
sample_range_a.select { |val| constant_range.include?(val) ? a++ : b++ }
end
constant_range = (240..960).to_a
sample_range = (540..1015).to_a
inside_count = (sample_range & constant_range).count #inside: 421
outside_count = sample_range.count - inside_count #outside: 55
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我来说两句