我必须在磁盘之间写入4GB short []数组，因此我找到了一个写入数组的函数，而且我正努力编写代码以从磁盘读取数组。我通常会使用其他语言编写代码，因此，如果到目前为止我的尝试有点可悲，请原谅我：
using UnityEngine;
using System.Collections;
using System.IO;
public class RWShort : MonoBehaviour {
public static void WriteShortArray(short[] values, string path)
{
using (FileStream fs = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write))
{
using (BinaryWriter bw = new BinaryWriter(fs))
{
foreach (short value in values)
{
bw.Write(value);
}
}
}
} //Above is fine, here is where I am confused:
public static short[] ReadShortArray(string path)
{
byte[] thisByteArray= File.ReadAllBytes(fileName);
short[] thisShortArray= new short[thisByteArray.length/2];
for (int i = 0; i < 10; i+=2)
{
thisShortArray[i]= ? convert from byte array;
}
return thisShortArray;
}
}
短裤是两个字节，因此您每次必须读两个字节。我还建议您使用yield return类似的代码，以免您一口气将所有内容拖入内存。虽然如果您一起需要所有短裤都不会帮到您..我想这取决于您在做什么。
void Main()
{
short[] values = new short[] {
1, 999, 200, short.MinValue, short.MaxValue
};
WriteShortArray(values, @"C:\temp\shorts.txt");
foreach (var shortInfile in ReadShortArray(@"C:\temp\shorts.txt"))
{
Console.WriteLine(shortInfile);
}
}
public static void WriteShortArray(short[] values, string path)
{
using (FileStream fs = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write))
{
using (BinaryWriter bw = new BinaryWriter(fs))
{
foreach (short value in values)
{
bw.Write(value);
}
}
}
}
public static IEnumerable<short> ReadShortArray(string path)
{
using (FileStream fs = new FileStream(path, FileMode.Open, FileAccess.Read))
using (BinaryReader br = new BinaryReader(fs))
{
byte[] buffer = new byte[2];
while (br.Read(buffer, 0, 2) > 0)
yield return (short)(buffer[0]|(buffer[1]<<8));
}
}
您还可以通过以下方式来定义它BinaryReader：
public static IEnumerable<short> ReadShortArray(string path)
{
using (FileStream fs = new FileStream(path, FileMode.Open, FileAccess.Read))
using (BinaryReader br = new BinaryReader(fs))
{
while (br.BaseStream.Position < br.BaseStream.Length)
yield return br.ReadInt16();
}
}
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