我尝试使用模拟器测试Firestore安全规则,但始终会发生超时错误...如果您有相同的现象或有解决方案,请告诉我。
测试结果
启动模拟器
% firebase serve --only firestore
运行测试
% yarn test
yarn run v1.19.2
$ jest
FAIL tests/firestore.test.ts (7.123s)
Firestore Security Rule
✕ sample1 (5044ms)
● Firestore Security Rule › sample1
: Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Error:
30 | });
31 |
> 32 | test("sample1", async () => {
| ^
33 | const db = createAuthApp();
34 | const user = usersRef(db).doc("test");
35 | await firebase.assertSucceeds(user.set({ name: "John" }));
at new Spec (node_modules/jest-jasmine2/build/jasmine/Spec.js:116:22)
at Suite.<anonymous> (tests/firestore.test.ts:32:3)
at Object.<anonymous> (tests/firestore.test.ts:16:1)
Test Suites: 1 failed, 1 total
Tests: 1 failed, 1 total
Snapshots: 0 total
Time: 8.038s
Ran all test suites.
error Command failed with exit code 1.
info Visit https://yarnpkg.com/en/docs/cli/run for documentation about this command.
环境
※Firestore安全规则允许所有由于样本
■firestore.test.ts
import * as firebase from "@firebase/testing";
import * as fs from "fs";
const PROJECT_ID = "firestore-rule-test";
const RULES_PATH = "firestore.rules";
// Create Firestore app with auth
const createAuthApp = (auth?: object): firebase.firestore.Firestore => {
return firebase
.initializeTestApp({ projectId: RULES_PATH, auth: auth })
.firestore();
};
const usersRef = (db: firebase.firestore.Firestore) => db.collection("user");
describe("Firestore Security Rule", () => {
beforeAll(async () => {
await firebase.loadFirestoreRules({
projectId: PROJECT_ID,
rules: fs.readFileSync(RULES_PATH, "utf8")
});
});
afterEach(async () => {
await firebase.clearFirestoreData({ projectId: PROJECT_ID });
});
afterAll(async () => {
await Promise.all(firebase.apps().map(app => app.delete()));
});
test("sample1", async () => {
const db = createAuthApp();
const user = usersRef(db).doc("test");
await firebase.assertSucceeds(user.set({ name: "John" }));
await firebase.assertSucceeds(user.get());
});
});;
在您的createAuthApp()
函数中,您正在使用项目ID初始化测试应用程序,RULES_PATH
但在测试中,您正在使用项目ID加载安全规则PROJECT_ID
。
改变中
.initializeTestApp({ projectId: RULES_PATH, auth: auth })
至
.initializeTestApp({ projectId: PROJECT_ID, auth: auth })
应该解决您的问题。
如果无法解决问题,您可以将Jest超时更改为5秒以上,--testTimeout=<number of ms>
以使测试有更多时间完成。
最后,为了清楚起见,考虑重新命名createAuthApp
,以createFirestoreInstance
作为“创建验证”意味着什么做的FirebaseAuth
类。
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句