以下是组织的样本文件
{
"org": {
"id": "org_2_1084",
"organizationId": 1084,
"organizationName": "ABC",
"organizationRoles": [
{
"addressAssociations": [
{
"activeDate": "2019-08-03T18:52:00.857Z",
"addressAssocTypeId": -2,
"addressId": 100,
"ownershipStatus": 1,
"srvAddressStatus": 1
},
{
"activeDate": "2019-08-03T18:52:00.857Z",
"addressAssocTypeId": -2,
"addressId": 105,
"ownershipStatus": 1,
"srvAddressStatus": 1
}
],
"name": "NLUZ",
"organizationRoleId": 893,
"roleSpecId": -104,
"statusId": 1,
"statusLastChangedDate": "2019-08-04T13:14:44.616Z"
},
{
"addressAssociations": [
{
"activeDate": "2019-08-03T18:52:00.857Z",
"addressAssocTypeId": -2,
"addressId": 582,
"ownershipStatus": 1,
"srvAddressStatus": 1
},
{
"activeDate": "2019-08-03T18:52:00.857Z",
"addressAssocTypeId": -2,
"addressId": 603,
"ownershipStatus": 1,
"srvAddressStatus": 1
}
],
"name": "TXR",
"organizationRoleId": 894,
"partyRoleAssocs": [
{
"partyRoleAssocId": "512"
}
],
"roleSpecId": -103,
"statusId": 1,
"statusLastChangedDate": "2019-08-04T13:14:44.616Z"
},
}和下面是地址的示例文档
{
"address": {
"address1": "string",
"address2": "string",
"addressId": "1531",
"changeWho": "string",
"city": "string",
"fxGeocode": "string",
"houseNumber": "string",
"id": "1531",
"isActive": true,
"postalCode": "string",
"state": "string",
"streetName": "string",
"tenantId": "2",
"type": "address",
"zip": "string"
}
}
在一个组织中有多个organizationRoles,在一个organizationRole中有多个addressAssociations。每个addressAssociation包含一个addressId,与此addressId相对应的地址存储在地址文档中。
现在,我必须从两个文档中获取organizationRole名称,organizationRole id,city,zip。在沙发床中获得最佳性能的最佳方法是什么?
我正在考虑使用连接,但无法针对这种情况提出确切的查询。我已经尝试了以下查询,但无法正常工作。
select *
from 'contact' As A UNNEST 'contact'.organizationRoles as Roles
UNNEST Roles.addressAssociations address
Join 'contact' As B
on address.addressID=B.addressID
where A.type="organization" and B.type="address";
您的方向正确。
在addressAssociations中,addressId是数字,在地址中,addressId是字符串。字符串和数字不相同,也没有隐式类型转换。您必须修复数据或使用TOSTRING(),TONUMBER()等进行显式类型转换...
同样,N1QL字段名称区分大小写(使用文档中的addressID与addressId进行查询)
SELECT r.name AS organizationRoleName, r.organizationRoleId, a.city, a.zip
FROM contact AS c
UNNEST c.organizationRoles AS r
UNNEST r.addressAssociations AS aa
jOIN contact AS a
ON aa.addressId = a.addressId
WHERE c.type = "organization" AND a.type = "address";
CREATE INDEX ix1 ON contact(addressId, city, zip) WHERE type = "address";
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我来说两句