如何将十进制数转换为二进制数，并将二进制数保存在数组中？

我现在无法对其进行测试，但这可能会有所帮助：

// Here there should be the necessary include to enable printing

unsigned int size = 10; // The size of the array that should store the bin output
int          a    = 3;  // The int to be converted to bin

// A function that returns a pointer to a byte, that will be interpreted as an array
unsigned short int
*IntToBin (int input)
{
    static unsigned short int output[size]; // Declaring the array to be returned by
                                            // the function, with keyword 'static' to
                                            // allow it to be referenced from outside
    for (int i = 0; i < size; i++) {
        output[i] = (input >> (size - 1 - i)) & 0x1; // Populating output array by
                                                     // bit-shifting the input int
                                                     // and doing a bitwise 'and' to
                                                     // keep only least significant
                                                     // digit
    }
    return output; // Returning the output array (an array is essentially a pointer,
                   // so this matches the function declaration)
}

// The main function, that will take care of calling the conversion function and
// printing its output
void
main ()
{
    unsigned short int result[] = IntToBin (a); // Assigns the output of the conversion
                                           // function to an array
    // Prints the input and output of the conversion function
    print("a = ");
    print(a);
    print("\na in bin = ");
    for (int i = 0; i < size; i++) {
        print (result[i]);
    }
    print("\n");
}

但是，如注释中所述，有符号的int的行为与无符号的int的行为不同。10输出数组的长度有点奇怪。

https://www.tutorialspoint.com/cprogramming/c_bitwise_operators.htm