我正在尝试制作一个可以识别文件夹名称是否为项目的脚本。为此，我想使用多个if条件。但是，我很难解决例如检查文件夹名称的首字母以及它是否为数字所导致的ValueError问题。如果是字符串，我想跳过该文件夹并检查下一个文件夹。预先感谢大家的帮助。干杯，本恩
我尝试了While和ValueError ：，但没有成功。
＃正确命名项目“ YYMM_ProjectName” =“ 1908_Sample_Project”
projectnames = ['190511_Waldfee', 'Mountain_Shooting_Test', '1806_Coffe_Prime_Now', '180410_Fotos', '191110', '1901_Rollercoaster_Vision_Ride', 'Musicvideo_LA', '1_Project_Win', '19_Wrong_Project', '1903_di_2', '1907_DL_2', '3401_CAR_Wagon']
＃检查条件
for projectname in projectnames:
if int(str(projectname[0])) < 3 and int(projectname[1]) > 5 and ((int(projectname[2]) * 10) + int(projectname[3])) <= 12 and str(projectname[4]) == "_" and projectname[5].isupper():
print('Real Project')
print('%s is a real Project' % projectname)
# print("Skipped Folders")
ValueError：int（）以10为底的无效文字：“ E”
根据我对所有ifs的了解...实际上，使用正则表达式匹配可能会更好。您正在解析每个字符，并期望每个单独的字符都在非常有限的字符范围内。
我尚未测试此模式字符串，因此它可能不正确，或者需要根据您的需要进行调整。
import re
projectnames = ['1911_Waldfee', "1908_Project_Test", "1912_WinterProject", "1702_Stockfootage", "1805_Branded_Content"]
p = ''.join(["^", # Start of string being matched
"[0-2]", # First character a number 0 through 2 (less than 3)
"[6-9]", # Second character a number 6 through 9 (single digit greater than 5)
"(0(?=[0-9])|1(?=[0-2]))", # (lookahead) A 0 followed only by any number 0 through 9 **OR** A 1 followed only by any number 0 through 2
"((?<=0)[1-9]|(?<=1)[0-2])", # (lookbehind) Match 1-9 if the preceding character was a 0, match 0-2 if the preceding was a 1
"_", # Next char is a "_"
"[A-Z]", #Next char (only) is an upper A through Z
".*$" # Match anything until end of string
])
for projectname in projectnames:
if re.match(p, projectname):
#print('Real Project')
print('%s is a real Project' % projectname)
# print("Skipped Folders")
编辑：=======================
您可以使用以下步骤逐步测试模式...
projectname = "2612_UPPER"
p = "^[0-2].*$" # The first character is between 0 through 2, and anything else afterwards
if re.match(p, projectname): print(projectname)
# If you get a print, the first character match is right.
# Now do the next
p = "^[0-2][6-9].*$" # The first character is between 0 through 2, the second between 6 and 9, and anything else afterwards
if re.match(p, projectname): print(projectname)
# If you get a print, the first and second character match is right.
# continue with the third, fourth, etc.
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