我希望条形图具有自己的标题和x轴标签,因此我在for循环中包括了plt.title
and plt.xlabel
。
但是,运行代码后,两个图形的标题和x轴标签都相同。第一张图Histogram of gender
的标题应为,第二张图的标题应为Histogram of job
。我的代码有什么问题,或者我做错了哪些部分,尤其是循环?
import matplotlib.pyplot as plt
import numpy as np
import seaborn as sns
import pandas as pd
from scipy import stats
# first data is age
# 2nd data is gender
# third data is saving
# 4th data is job
data = np.array([[11, "male",1222,"teacher"],[23,"female",333,"student"],
[15,"male",542,"security"],[23,"male",4422,"farmer"],[25,"female",553,"farmer"],
[22, "male", 221, "teacher"],[27, "male", 333, "agent"],[11, "female", 33, "farmer"]])
data_feature_names = ["age","gender","saving","job"]
# type of the data above
types = ["num","cat","num","cat"]
idx2 = []
for index, _type in enumerate(types):
if _type == 'cat':
idx2.append(index)
# Order of x axis label
ss = [["female","male"],["farmer","agent","security","teacher","student"]]
for k in range(0,len(ss)):
for j in idx2:
pandasdf = pd.DataFrame(data)
sns.countplot(x=j, data=pandasdf, order = ss[k])
plt.title("Histogram of " + data_feature_names[j])
plt.xlabel(data_feature_names[j])
plt.show()
您的订购顺序ss
和列名称idx2
是配对的,因此您可以使用一个循环并最终获得所需的性别和工作直方图结果(但在这种情况下,您不会最终获得年龄或储蓄的直方图)。您的示例的最后几行将变为:
for k, j in zip(range(0, len(ss)), idx2):
pandasdf = pd.DataFrame(data)
sns.countplot(x=j, data=pandasdf, order=ss[k])
plt.title("Histogram of " + data_feature_names[j])
plt.xlabel(data_feature_names[j])
plt.show()
您可以通过几种方法来简化此过程,以便于调试。例如,您可以idx2
使用列表理解来缩短循环时间:
idx2 = [ix for ix, f in enumerate(types) if f == "cat"]
我在下面提供了另一个示例,其中包含较少的代码行,但是对原始脚本进行了更多修改。
import matplotlib.pyplot as plt
import seaborn as sns
import pandas as pd
data = pd.DataFrame(
[
[11, "male", 1222, "teacher"],
[23, "female", 333, "student"],
[15, "male", 542, "security"],
[23, "male", 4422, "farmer"],
[25, "female", 553, "farmer"],
[22, "male", 221, "teacher"],
[27, "male", 333, "agent"],
[11, "female", 33, "farmer"],
],
columns=["age", "gender", "saving", "job"],
)
ordering = {
"gender": ["female", "male"],
"job": ["farmer", "agent", "security", "teacher", "student"],
}
for column in ['gender', 'job']:
ax = sns.countplot(x=column, data=data, order=ordering.get(column, None))
ax.set_title("Histogram of {}".format(column))
ax.set_xlabel(column)
plt.show()
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