通过匹配ID组合JSON数组的值-

马修

我正在尝试结合JSON对象的值以显示发往特定目标的流量的完整吞吐量，而不是显示相同地址的微小值。

我已经阅读了数百个线程，它们似乎都围绕着使用单个键将不同数组中的值添加到一个数组中，或者将这些值组合到一个字段中来进行。

此处的关键是IP地址，要添加的值是RX和TX

我的数据如下所示：

[
  {"macProtocol": "ip", "ipProtocol": "tcp", "dstAddress": "X.60.219.13", "tx":50, "rx":100},
  {"macProtocol": "ip", "ipProtocol": "tcp", "dstAddress": "X.60.219.13", "tx":50, "rx":100},
  {"macProtocol": "ip", "ipProtocol": "tcp", "dstAddress": "X.60.219.13", "tx":50, "rx":100},
  {"macProtocol": "ip", "ipProtocol": "tcp", "dstAddress": "X.60.219.13", "tx":50, "rx":100},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.172.63.97", "tx":500, "rx":750},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.189.157.90", "tx":1000, "rx":2776},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.212.176.21", "tx":70, "rx":300},
]

我想将其转换为：

[
  {"macProtocol": "ip", "ipProtocol": "tcp", "dstAddress": "X.60.219.13", "tx": 200, "rx": 400},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.172.63.97", "tx": 500, "rx": 750},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.189.157.90", "tx": 1000, "rx": 2776},
  {"macProtocol": "ip", "ipProtocol": "udp", "dstAddress": "X.212.176.21", "tx": 70, "rx": 300},
]

大师

您可以创建目标地址的哈希：

let data = [
  {
    macProtocol: 'ip',
    ipProtocol: 'tcp',
    dstAddress: 'X.60.219.13',
    tx: 50,
    rx: 100,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'tcp',
    dstAddress: 'X.60.219.13',
    tx: 50,
    rx: 100,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'tcp',
    dstAddress: 'X.60.219.13',
    tx: 50,
    rx: 100,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'tcp',
    dstAddress: 'X.60.219.13',
    tx: 50,
    rx: 100,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'udp',
    dstAddress: 'X.172.63.97',
    tx: 500,
    rx: 750,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'udp',
    dstAddress: 'X.189.157.90',
    tx: 1000,
    rx: 2776,
  },
  {
    macProtocol: 'ip',
    ipProtocol: 'udp',
    dstAddress: 'X.212.176.21',
    tx: 70,
    rx: 300,
  },
];
const reducedArr = Object.values(
  /*obj:  {
  'X.212.176.21': {
    macProtocol: 'ip',
    ipProtocol: 'udp',
    dstAddress: 'X.212.176.21',
    tx: 70,
    rx: 300,
  }, 
  'X...':{},
  .....
  }*/
  data.reduce((obj, {dstAddress:dAdd,...curr}) => {
    if (dAdd in obj) {
      ['tx', 'rx'].forEach(x => (obj[dAdd][x] += curr[x]));
    } else {
      obj[dAdd] = curr;
    }
    return obj;
  }, {})
);

console.log(reducedArr);

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