我试图将输入作为整数,例如1 2 3 4 5
,之间用空格隔开12345
。我需要在它们之间留出空间,以便我可以计算和处理中值,众数,均值和标准差。请注意,我之前已经尝试Integer.parseInt()
过。
import javax.sound.midi.SysexMessage;
import java.util.Arrays;
import java.util.*;
import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;
import javafx.application.Application;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.stage.Stage;
import javafx.scene.text.Text;
public class FinalProg {
Button button;
public static void main(String[] args) {
// int[] dataSet = {1,2,3,4,345,312,756,0,-234321132,234};
// int[] dataSet = {5,3,2,5,2,5,758,345,32,231,5,5,5,2,2};
// Scanner scanner = new Scanner(System.in);
// String input = scanner.nextLine();
//
//
//
//
//
//
//
//
//
// int [] dataSet = new int[input.length()];
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine(); //Numbers inputted from user in your case
String[] list; //List to store individual numbers
list = input.split(" "); // Regex to split the String so you get each number
//Mean
int sum = 0;
for (String n : list) {
sum += Integer.parseInt(n);
}
System.out.println("The mean of the data set is " +
((double) sum / list.length));
//Median
Arrays.sort(list);
if (list.length % 2 != 0) {
System.out.println("The median of the data set is: " + Double.parseDouble(list[list.length / 2]));
} else {
System.out.println("The median of the data set is: " + Double.parseDouble(list[list.length / 2] + list[list.length / 2 - 1]) / 2.0);
}
//Mode
int maxNumber = -1;
int maxAppearances = -1;
for (int i = 0; i < list.length; i++) {
int count = 0;
for (int j = 0; j < list.length; j++) {
if (list[i] == list[j]) {
count++;
}
}
if (count > maxAppearances) {
maxNumber = Integer.parseInt(list[i]);
maxAppearances = count;
}
}
System.out.println("The mode of the data set: " + maxNumber);
//STDV
double STDVsum = 0.0, standardDeviation = 0.0;
int length = list.length;
for(String num : list) {
STDVsum += Double.parseDouble( num);
}
double mean = STDVsum/length;
for(String num: list) {
standardDeviation += Double.parseDouble(Math.pow(num - mean, 2)); // It says operator - doesn't apply...
}
System.out.println( "STDV "+ Math.sqrt(standardDeviation/length));
}
}
}
我希望有一个像1 2 3 4 5
处理和计算这样的输入,而不是采用12345
。如您在上面的代码中所见,我有一个整数数组,但是在这种情况下缺少带空格的输入
编辑:(新更新)该示例的结果显示为:
2 3 4 5 6 7 6 6数据集的平均值是4.875数据集的中位数是:32.5数据集的模式:2
但是正确的结果是:
均值:4.875中位数:5.5模式:6
另外,由于无法转换,所以无法计算STDV:standardDeviation + = Double.parseDouble(Math.pow(num-mean,2));
为此,只需问用户输入的数字是否为字符串,然后用.split(“”)拆分,然后将其解析为整数即可。
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine(); //Numbers inputted from user in your case
String[] list ; //List to store individual numbers
list = input.split(" "); // Regex to split the String so you get each number
int sum = 0; //Your sum
for(String i : list) //Iterate through Array
{
sum += Integer.parseInt(i); //Parse the string value as int to your sum
}
System.out.println(sum); // to check if everything worked fine
关于您面临的其他问题:中位数是错误的,因为这里:
System.out.println("The median of the data set is: " + Double.parseDouble(list[list.length / 2] + list[list.length / 2 - 1]) / 2.0);
您不考虑list [list.length / 2]值是一个字符串。修复了如下问题:
float median = (Integer.parseInt(list[list.length/2]Integer.parseInt(list[(list.length/2)-1])) / 2f ;
System.out.println("The median of the data set is: " + median);
关于模式问题,您只是再次忘记了您正在处理一个字符串数组,并以错误的方式检查了on是否等于另一个:
if (list[i] == list[j]) {
count++;
}
如果您要检查2个字符串是否相等,可以这样进行
if (list[i].equals(list[j])) {
count++;
}
我也认为您需要在检查每个数字后重新设置计数,因此也请在此处添加:
if (count > maxAppearances) {
maxNumber = Integer.parseInt(list[i]);
maxAppearances = count;
}
count=0;
}
在这种情况下,STDV问题num仍然是字符串,因此您不能在其上调用Math.pow:
standardDeviation += Double.parseDouble(Math.pow(num - mean, 2));
通过将num解析为int来修复
for(String num: list) {
int num_to_Integer = Integer.parseInt(num);
standardDeviation += Math.pow(num_to_Integer - mean, 2); //No need to parse now
}
检查STDV现在是否返回正确的结果。
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