如何将base13字符串转换为base64

我必须为查询字符串创建一个URL缩短器。花了几天时间尝试将数组数据压缩为base64字符串。认为最好的方法可能是将诸如[[1,2,9,3]，[1,0,2]，[39,4]]之类的东西解释为以数字0-9和[]为符号的base13 。

当前算法的工作原理：将字符串化数组转换为base13数组，其中每个元素表示1个唯一字符，将此数组转换为base10数字，将此数字转换为base 64字符串。

但是问题是当将base13数组转换为base10数字时，它使5.304781188371057e + 86之类的大数字无法保存在js中。

我当然可以选择其他解决方案，但是请不要建议创建URL数据库之类的东西，因为它最多只能支持51个！* 51！唯一的URL，最好仅制作一个紧凑的可编码和可解码查询字符串，并在访问网站后立即对其进行解码。

//convert stringified array to array of base13(each element = each digit of base13 number)
function stringToArray(string)
{
    let charSet = "[],1234567890";
    let array = [];
    for(let i = 0; i < string.length; i++)
    {
        array.push(charSet.indexOf(string[i]));
    }
    return array;
}

//convert base13 array to one large decimal number
function arrayToDecimal(array, base)
{
    var decimal = 0;
    for(let i = 0; i < array.length; i++)
    {
        decimal += array[i] * Math.pow(base, i)
    }
    return decimal;
}

//convert decimal number back to array
function decimalToArray(decimal, base)
{
    var quotient = decimal;
    var remainder = [];
    while(quotient > base)
    {
        remainder.push(quotient % base)
        quotient = Math.floor(quotient / base);
    }
    remainder.push(quotient % base)
    return remainder;
}

const alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/';

// binary to string lookup table
const b2s = alphabet.split('');

// string to binary lookup table
// 123 == 'z'.charCodeAt(0) + 1
const s2b = new Array(123);
for(let i = 0; i < alphabet.length; i++)
{
    s2b[alphabet.charCodeAt(i)] = i;
}

// number to base64
const ntob = (number) =>
{
    if(number < 0) return `-${ntob(-number)}`;

    let lo = number >>> 0;
    let hi = (number / 4294967296) >>> 0;

    let right = '';
    while(hi > 0)
    {
        right = b2s[0x3f & lo] + right;
        lo >>>= 6;
        lo |= (0x3f & hi) << 26;
        hi >>>= 6;
    }

    let left = '';
    do {
        left = b2s[0x3f & lo] + left;
        lo >>>= 6;
    } while(lo > 0);

    return left + right;
};

// base64 to number
const bton = (base64) =>
{
    let number = 0;
    const sign = base64.charAt(0) === '-' ? 1 : 0;

    for(let i = sign; i < base64.length; i++)
    {
        number = number * 64 + s2b[base64.charCodeAt(i)];
    }

    return sign ? -number : number;
};



console.log(decimalToArray(bton(ntob(arrayToDecimal([1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], 13))), 13)) 
//encoded and decoded, works output:[1,1,1,1,1,1,1,1,1,1,1,1,1]
console.log(arrayToDecimal([1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], 13)) 
//encoding doesnt work, array to decimal converts to 5.304781188371057e+86```