如何打印从文本文件读取的行中与正则表达式匹配的字符串的唯一部分。我有以下代码。
filename = "C:/Users/Desktop/netlist"
pattern = re.compile('^[A-Z]{1,2}\d{1,3} ')
with open(filename, "rt") as myfile:
for line in myfile:
if pattern.search(line) != None:
print(line, end='')
但这给了我包含匹配的整行。
我尝试过的另一件事是。
k = []
filename = "C:/Users/Desktop/netlist"
pattern = re.compile('^[A-Z]{1,2}\d{1,3}')
with open(filename, "rt") as myfile:
for line in myfile:
if pattern.match(line) != None:
k.append(pattern.search(line))
但这以re.Match对象而不是列表的形式出现
[<re.Match object; span=(0, 3), match='NM4'>,
<re.Match object; span=(0, 3), match='NM3'>,
<re.Match object; span=(0, 2), match='M9'>,
<re.Match object; span=(0, 2), match='M7'>,
<re.Match object; span=(0, 2), match='M5'>,
<re.Match object; span=(0, 2), match='M2'>]
我的输入看起来像：
NM4 (net19 net19 0 0) nmos1 w=(5.65u) l=410n as=3.39p ad=3.39p ps=12.5u \
NM3 (net28 net19 0 0) nmos1 w=(5.65u) l=410n as=3.39p ad=3.39p ps=12.5u \
M9 (vout\+ net19 0 0) nmos1 w=(12.71u) l=310n as=7.626p ad=7.626p \
M7 (vout\- net19 0 0) nmos1 w=(12.71u) l=310n as=7.626p ad=7.626p \
M5 (net7 net19 0 0) nmos1 w=(2u) l=180n as=1.2p ad=1.2p ps=5.2u pd=5.2u \
M2 (net8 Vin\- net7 0) nmos1 w=(28.25u) l=410n as=16.95p ad=16.95p \
我希望我的答案看起来像：
[NM4 NM3 M9 M7 M5 M2]
使用正则表达式分组 '([A-Z]{1,2}\d{1,3})'
例如：
k = []
filename = "C:/Users/Desktop/netlist"
pattern = re.compile('([A-Z]{1,2}\d{1,3})')
with open(filename, "rt") as myfile:
for line in myfile:
m = pattern.match(line)
if m: #Check if data.
k.append(m.group(1)) #Fetch result.
print(k) #['NM4', 'NM3', 'M9', 'M7', 'M5', 'M2']
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